求圆x^2 y^2_2x-3=0与坐标轴的交点
来源:学生作业帮助网 编辑:作业帮 时间:2024/09/29 21:08:18
(2x+y)/(x^2-2xy+y^2)X(x-y)=(2x+y)/(x-y)²*(x-y)=(2x+y)/(x-y)x-3y=0,x=3y(2x+y)/(x-y)=(6y+y)/(3y-y
解析交点第四象限所以x>0y0k>-2又y再问:额,抱歉,能告诉我kx+2
2x-3y=0(1)3x-y-1=0(2)由(2)得y=3x-1(3)把y=3x-1代入(1)得2x-9x+3=0∴x=3/7把x=3/7代入(3)得y=2/7∴x=3/7y=2/7
由题意可得如下方程组:3x-y+5=02x-y+3=0解得:x=-2y=-5/2再问:很可惜思路对了得数错了Y=-1你是第一个回答我的还是选你吧
12再答:15再答:X1Y5
原方程左边=(2x-y)(x+2y)=0所以x=y/2或x=-y/2将x的值分别代入到x+y/x-y得-3或-1/3
4x-2y=0→y=2x,把所有的y都用2x替代.结果是-1/7
依题意得f(x)=log1/2(_x²_2x+3)设u(x)=-x²-2x+3得u(x)=-(x+1)²+4则其定义域为x∈(-3,1)又因为log1/2u为u>0上的减
绝对值和开根号都是大于等于0的,他两相加等于0说明都是0,分别算就行了,xy都是0
1.顶点:x=1y==a-1/2∵y=-2x∴a-1/2=-2a=-3/22.y=1/2x²-x-3/2则1/2x²-x-3/2=0x=-1,3交点(-1,0)(3,0)3.C(0
x=3y所以原式=11y/7y=11/7
X+Y分之X-Y等于3x=-2yX+Y分之2(x-y)减X+Y分之3X+Y=(-x-3y)/(x+y)=1
2x=2-3yx>0则2x>0所以2-3y>0y
因为(x-y)/(x+y)=3,则(x+y)/(x-y)=1/3则5(x-y)(x+y)-(x+y)/2(x-y)=5*3-1/(3*2)=15-1/6=89/6
3x^2+xy-2y^2=0推出(3x-2y)(x+y)=0推出x=-y或x=(2/3)y{(x+y)/(x-y)+4xy/(y^2-x^2)}/{(x+3y)*(x-y)}/x^2-9y^2推出:{
解,因为|x+2y+3|+(2x+y)²=0所以|x+2y+3|=0,(2x+y)²=0所以:x+2y+3=0.2x+y=0解得x=1y=-2x²-xy+y²=
2x-3y=02x=3yx=1.5y5x+4y/3x-2y=7.5y+4y/4.5y-2y=11.5y/2.5y=4.6
2x+y+3=xy,①若x=1,则y不存在,此时5x+4y无最值;②若x≠1,则y=(2x+3)/(x-1),M=5x+4y=5x+(8x+12)/(x-1)=(5x²+3x+12)/(x-
∵x^2-3y^2=2xy∴x^2-2xy-3y^2=0∴(x+y)(x-3y)=0∵x>0,y>0∴x-3y=0∴x=3y∴x+2y/x-y=3y+2y/3y-y=2y+2/3或=2/3(x+1)如