生成多项式x^15 1分解
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/13 16:54:29
原式=(x²-4y²)+x-2y=(x+2y)(x-2y)+(x-2y)=(x-2y)(x+2y+1)
解题思路:比较系数法解题过程:见附件最终答案:略
如图···望采纳!
m^2(x-y)+m(y-x)=m²(x-y)-m(x-y)=m(x-y)(m-1)
2x-4x^2=2x(1-2x)18x^3-2xy^2=2x(9x^2-y^2)=2x(3x-y)(3x+y)
3x²+xy-2y²=03x-2yxy所以分解化为:(3x-2y)(x+y)=0
/>(1)原式=(x+2y)(x-2y)+x-2y=(x-2y)(x+2y+1)第二题狮子看不清,能在描述一遍吗再问:分解因式:(x²+1)²-x²+x(x-2)(x
当m=-3时,2x2+5x-3=(2x-1)(x+3).
(x-2)²-4x+12=x²-4x+4-4x+12=x²-8x+16=(x-4)²
据x^3的系数是2设(2x+1)(x^2+bx+c)=2x^3-x^2-13x+k=2x^3+(2b+1)x^2+(2c+b)x+c2b+1=-1b=-12c+b=2c-1=-13c=-7k=c=-7
x2-x-2=(x-2)(x+1).故答案为:(x-2)(x+1).
先求出C的值,(X+1)(x+2)去括号得到x²+3x+2=,与前一式对照得到c=2再将c=2带入x²-3x+c中并分解因式得到x²-3x+2=(x-1)(x-2)
x^2-2xy+y^2+4y-4x+4=(x-y)^2-4(x-y)+4=(x-y-2)^2
根据题意可设x^3-3x+k=(x-1)(x²+ax-k)=x³+(a-1)x²-(a+k)x+k(根据十字相乘的规律所设)对比左右各项系数可知:a-1=0a=1-(a+
2x²-5x-3=(2x+1)(x-3)
(2x-y)(3x+5y)=6x^2+10xy-3xy-5y^2=6x^2+7xy-5y^2希望采纳
很高兴回答你的问题:4x²-(x²+1)²=(2x+x²+1)(2x-x²-1)=-(x+1)²(x-1)²
m²(x—2)+m(2—x)=(x—2)-m(x-2)=(m²-m)(x-2)=m(m-1)(x-2)
(x+1)(x-2)=x²-x-2则:a=-1,b=-2