用c语言编程求圆的面积的编程运行截图

根据提示做是没问题的.先定义数组：intA[50];在提示基础上略加修改：inti=0,sum=0;floatavg;for(;scanf("%d",&A[i])==1&&i

你这个怎么看都是错的第一,主函数是这样定义的吗第二,这里乘法运算需要把float型转化为double型最后,没有返还函数,了return0；改正如下：#include#definePI3.14159i

#include#includevoidmain(){floatc,d,f,a,b;a=-10;b=10;while(fabs(a-b)>=0.000001){c=(a+b)/2;d=2*a*a*a-

程序流程分析：①赋值x0＝1.5,即迭代初值；②用初值x0代入方程中计算此时的f(x0)及f’(x0),程序中用变量f描述方程的值,用fd描述方程求导之后的值；③计算增量d=f/fd；④计算下一个x,

#include#includeintmain(){floats,a,b,c,p;printf("请输入三角形的三边,以空格隔开");scanf("%f%f%f",&a,&b,&c);if(a+b>c

什么报错?再问：就只有这个Cpp12.obj-1error(s),0warning(s)再答：你看下那个错误具体是什么，写一下。再问：--------------------Configuration

#include"stdio.h"doubleY(doublex){returnx-1?1.0/(1+x):0;}intmain(){\x05doublex;\x05scanf("%lf",&x);p

1.#includeintmain(){floatr,s,l,v;printf("请输入半径\n");scanf("%f",&r);s=3.14*r*r;l=2*3.14*r;v=4.0/3.0*3.

#includevoidmain(){doublex=2.5;inta=7.0;doubley=4.7;doublez;z=x+a%3*(int)(x+y)%2/4;printf("%f",z);}

#include"stdio.h"#definePI3.14intmain(){floatarea,sum=0;for(inti=1;i

main(){inta,b,c;scanf(%d,%d,%d,a,b,c);printf(%f,(a+b+c)/3);}

#include#definePremeter(a,b)2*(a+b)#defineArea(a,b)a*bintmain(){doublea,b;printf("请输入矩形的长和宽:\n");sca

知道三边,利用海伦公式求面积.#include#includeintmain(){doublea,b,c,p;scanf("%lf%lf%lf",&a,&b,&c);p=(a+b+c)/2;print

#include"stdio.h"voidmain(){longa=1,n,s=0;for(n=1;n

#include#includemain(){doublearea,length;doubler=pi=3.1215926area=pi*r*r；length=2*pi*r；}

#includeintmain(){inta,b,c,average;printf("a=");scanf("%d",&a);printf("b=");scanf("%d",&b);printf("c

#includeusingnamespacestd;voidmain(){inta,b,c;cin>>a>>b>>c;intk=a;while(1){\x05if((k%a==0)&&(k%b==0)

//printf里面多了个&,没注意啊#include//data:原来的数//fun(data)运算后的数/*63.4564*100->6345.64+0.5->6346.14强制转化成int->6

第一题#includeintmain(){intsum=21,i,a=0,b=0,c=0,xs=1;for(i=0;i

if((e+c