用元胞体数组求平均值

#include<stdio.h>void main(){ int a[10]={89,80,95,84,73,84,91,78,87,94}; i

是前n个元素么?main(){inti=n,sum=0;max=a[0];min=a[0];for(i=0;ia[i])?max:a[i];min=(min再问：输出的avg不是整数再答：哎呀，忘了这

while(*p)无法判断数组何时结束,不妨设一个计数器countintcount=10;while(count>0)//移动指针进行操作count--;还有一点就是如果是C++代码的话头文件请如下写

OptionBase1OptionExplicitDima(11)AsIntegerPrivateSubCommand1_Click()DimiAsIntegerPicture1.ClsPicture

#inlcudevoidmain(){inta[6];inti,j,max=0,sum=0;doubleavg=0.0;printf("请输入六个数：\n");for(i=0;imax)max=a[i

Dima(1To10)AsInteger'定义10个数组Dimaa(1To9)AsInteger'定义9个空格数组DimnAsInteger'定义空格数DimsAsInteger'数组和Form1.C

PrivateSubCommand1_Click()Dima(6,10)AsIntegerDimiAsIntegerDimmAsIntegerFori=0To10Form=0To6a(m,i)=Rnd

祝你学习愉快!#include#defineN20intmain(){//声明被调用函数!voidmax(intb[],intn);voidmin(intb[],intn);voidaver(intb

#include#includemain(){inta[10],i,p=0;floatv=0.0,temp;for(i=0;i

楼上的似乎没有按题目要求做,我改了一下,你看看吧#includefloatcountAvg(inta[10]){/*这个函数求平均值*/inti,sum=0;floatavg;for(i=0;i

#include#include#includeintmain(){srand((unsigned)time(0));intArray[10];inti=0;doublesum=0;intMax=-1

#include#defineN10voidmain(void){inta[N]={21,5,54,1,654,3,56,87,546,6};inti;intmin;//最小值intmax;//最大值

FunctionAverage(mySinge()AsSingle)AsSingleDimsnAsSingleDimcnAsInteger,iAsIntegercn=UBound(mySinge)-L

Private Sub Command1_Click()Dim i As Integer, j As Integer,&

看看谁的效率高过我importjava.util.Arrays;importjava.util.InputMismatchException;importjava.util.Scanner;publi

#include#defineN20//默认数组大小20intmain(){inta[N],i;doubleave=0;printf("输入20个数\n");for(i=0;i

#include"stdio.h"voidmain(){inta[10],max,min,i,j,n,s=0;floatping=0,he=0;for(i=0;i

所要求的程序已经完成,#include<stdio.h>#include<stdlib.h>main(){ inta[100],i,s=0; randomi

C语言编写#include#includevoidmain(){intnum[20];//用来存放随机产生的20个数inti,j,sum,max,min,average;//sum,max,min,a

#include#includevoidmain(){inta[10];intsum=0;intbelow_ave=0;floatave=0;inti;printf("inputteninteger: