用指针法统计10个数中正数,负数和零的个数,并分别求正数的总和,负数的总和-搜答案-智慧作业帮

=COUNTIF(A1:A100,">0")

"float*Grade(float*num,inti)//用来冒泡排序num传入数组指针,i传入数组个数{intj,k;floattemp;for(j=0;j<i;j++)for(k=0;k&

改好了#includeintn,m,a[100];intmain(){voidshuru(intn);voidexchange();inti;printf("请依次输入n,m的值：");sc

比实际值偏小

供参考……#include"stdio.h"//voidmain(void){intnDec[10]={7,1,9,2,6,0,3,5,4,8},i,max,min;printf("Type10int

#include#includevoidmain(){\x09inta[100],b[100],m,n,i;\x09printf("输入几个数?\n");\x09scanf("%d",&n);\x09

#include#include#defineLENGTH20voidmain(){int*pBuff=(int*)malloc(sizeof(int)*LENGTH);inti,max,min;fo

统计DA_WORD数据区中正数、0、负数的个数,数据定义如下：DA_WORDDW-1,3,5,0,-5,-7,4,0,-8……COUNTEQU$-DA_WORDNUMDB0；存放正数的个数DB0；存放

#include#includemain(){inti,j,m,n,a[1000];scanf("%d",&i);//数的个数for(j=0;j

#include#defineN10intmain(){inti,zh,fu,ling;inta[N];int*pa;pa=a;for(i=0;i

-19,-199,（2n-1）乘以-1的n-1次幂

#includevoidmain(){inta[10],i,*m,*n,k=0;\x09printf("请输入十个数\n");for(i=0;i

#includeintmain(){inta[10]={1,-1,2,0,5,-6,7,0,-2,0};inti,num_po=0,num_in=0,num_ze=0;for(i=0;i0)num_p

for(p=a+1;p*max)max=p;elseif(*p

intmain(void){\x09inti=0,j=0,n;\x09printf("\ninputnumbers:");\x09scanf("%d",&n);\x09//\x09\x09scanf(

n平方+1乘-1的n+1次方再问：真假再答：你带值ShiShi再答：试试

#include#defineN10voidmain(){intx[N],i,*pmax,*pmin,k;for(i=0,p=x;i

printf("请输入十个正整数:\");x=(int*)array;for(i=0;iscanf("%d",&j);j=j>0?j:-j;/*保证输入为正整数*/if(maxif(min>j){/*

我只看见40个啊

即使拿走了,但是另一侧电量还是没有变,因为,电子没有做运动,还存在哪里.