java倒序输出4位整数

#includevoidmain(){intn,m;scanf("%d",&n);while(n){m=n%10;//取末位的数字printf("%d",m);n/=10;//去掉末位}printf(

publicclassPrintUpperChar{publicstaticvoidmain(String[]args){for(charM='Z';M>='A';M--){System.out.pr

分两步呗.第一步：生成随机数第二步：排序这里只说第一步的内容,第二步,我想你的算法书中都有说吧.先说生成一个0-1之间的随机数很容易吧?doublek=Math.Random();而获得一个0-100

importjava.util.Scanner;publicclassSum{publicstaticvoidmain(String[]args){Scanners=newScanner(System

importjava.io.*;classSEV{publicstaticvoidmain(String[]args)throwsIOException{intmax,min;doublesh;Inp

importjava.util.Arrays;importjava.util.Scanner;publicclassDataCompare{\x09publicstaticvoidmain(Strin

#include"stdio.h"voidprint(intx){printf("%d",x%10);if(x>=10)print(x/10);}voidmain(){intn;scanf

DimxAsInteger,sAsString,dAsStringRandomizex=Int(Rnd()*9000+1000)s=Str(x)d=Right(s,1)+Mid(s,4,1)+Mid(

publicclassTest{publicstaticvoidmain(String[]args){inta=1203;intsum=0;while(a/10!=0){sum

staticvoidBubbleSort(inta[]){inttemp=0;for(inti=0;ifor(intj=0;jif(a[j]>a[j+1]){//把这里改成大于,就是升序了temp=a

importjava.util.ArrayList;importjava.util.Collections;importjava.util.Comparator;importjava.util.Has

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

publicclassTest{publicstaticvoidmain(String[]args){inta=Integer.parseInt(args[0]);intn=Integer.parse

importjava.util.Scanner;publicclassjiechen{publicstaticvoidmain(String[]args){Scannerscanner=newScan

publicvoidscanner(){\x09\x09intarr[]=newint[5];//存储输入数据\x09\x09inttemp;\x09\x09\x09\x09//用于数据交换\x09S

倒序应该是testaisthis如果你确定是testisathis,那么下面的代码对你没有帮助publicclassMain{publicstaticvoidmain(String[]args){St

//eg1.javaimportjava.util.*;publicclasseg1{publicstaticvoidmain(String[]args){inta=0,b=0,c=0,max=0;S

importjava.util.*;publicclassExercise06{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

楼上说没错,while(X)是先进行X判断然后再执行{语句体},而do..while则是先执行do{语句体},再判断while(X),这样会导致do..while比while执行语句体的次数多一次再问