java输入6个数 找出最大最小及其位置
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input"请输入第一个数:"toainput"请输入第二个数:"tobinput"请输入第三个数:"toc?"最大值为:",max(a,b,c)
测试通过,基本满足你题目要求,写得不太好importjava.util.*;importjava.util.regex.*;publicclasst10{publicstaticvoidmain(St
publicclassMax{publicstaticvoidmain(String[]args){int[]a=newint[5];System.out.println("请输入五个数:");Sca
1、clearinput"输入个数"tondimensiona[n]fori=1toninput"输入第"+alltrim(str(i))+"个数"toa[i]endformax=a[1]min=a[
vara:array[1..1000]ofinteger;n,i,j,k:integer;beginreadln(n);j:=1;fori:=1tondobeginread(a[i]);ifa[i]
CLSDIMa(10)FORi=1TO10INPUTa(i)NEXTiFORi=1TO9FORj=i+1TO10IFa(i)NEXTj,iPRINTa(1),a(10)end
1.clearinput"请输入要比较的数个数:"tondimea(n)fori=1toninput"第"+alltrim(str(i))+"个数:"toa(i)endforstorea(1)toma
//#includeintmain(){inta[10],i,max,min;for(i=0;i{scanf("%d",&a[i]);//输入十个数if(i==0)//初始化最大值,最小值的位置为0m
#includeintmain(){inta[10],i,*maxInt,*minInt;for(i=0;i{printf("输入第%d个整数:\n",i+1);scanf("%d",&
vari,n,m,max,min:longint;beginreadln(n);max:=-maxlongint;min:=maxlonint;//初始化fori:=1tondobeginreadln
#includeintmain(){inti,max,min,maxnum,minnum;inta[10]={0};for(i=0;i再问:有些不懂啊?怎么是intmain?inta[10]只定义不赋
#includeintmain(){inta,b,c,min,max;printf("请输入三个数,用空格键隔开");scanf("%d%d%d",&a,&b,&c);min=ac?b:c);prin
34219856073421985607max=9,min=0Pressanykeytocontinue#includemain(){inti,input[10],smax,smin,sum=0;
#include#defineN10//修改这个数可以改变数组的大小main(){inta[N],i,max,min;floataver=0;printf("请输入%d个正数!\n",N);for(i
size=0;while(size
dimensions(10)fori=1to10input"请输入s(i)的值"tos(i)nexti
#includeusingnamespacestd;voidmain(){inti,n;floata[50],sum=0.0,ave,min;coutn;for(i=0;i
1、输入4个数a,b,c,d2、定义变量x,3、赋值:x=a,4、判断x
importjava.io.*;publicclassTest{publicstaticvoidmain(String[]args){BufferedReaderbr=newBufferedReade
importjava.uti.Scanner;publicclasstest{publicstaticvoidmain(String[]args){Scannerscanner=newScanner(