编写Java应用程序,把100~1000的自然数中能够被3整除的数输出到屏幕上

publicclassA3{publicstaticvoidmain(String[]args){for(inti=1;i

importjava.io.*;importjava.util.*;classMain{publicstaticintgcd(intm,intn){while(true){if((m=m%n)==0)

publicstaticvoidmain(String[]args){doubleresult=0;for(inti=1,j=1;i

先定义一个2行9列的二维数组,可以看成是两个一维数,每个一维数组有九个元素,然后分别给两个数组赋值（1,2,3,4,5,6,7,8,9这些值）；最后就是两个数组间的元素分别相乘了,按一定顺序相乘即得乘

importjava.util.Scanner;classRound{\x09publicdoubleperimeter(doubleradius){\x09\x09returnradius*2;\x

importjava.util.Scanner;publicclassCircle{    publicstaticvoidmain(String[]args)

代码如下,我已经测试过了,给你加了注释.publicclassTest{publicstaticvoidmain(Stringargs[]){for(inti=100;i再问：------------

publicstaticStringtranslate(Stringvalue){StringBufferresult=newStringBuffer();char[]valueChars=value

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){System.out.print("请输入第一个整

importjava.io.BufferedReader;importjava.io.IOException;importjava.io.InputStreamReader;importjava.ut

做回好人,回答你吧.直接看代码：importjava.io.File;importjava.io.FileInputStream;importjava.io.FileNotFoundException

我的代码：publicclassTest{publicstaticvoidmain(String[]args){inti=1;intsum=0;while(i

public class Test{    public static void main(String&nb

publicclasssum{privatedoublesum=0;publicvoidgetSum(){intj=1;for(doublei=1;i

publicclasstest{publicstaticvoidmain(Stringargs[]){System.out.println("N\t10*N\t100*N\t1000*N");for(

importjava.util.Scanner;publicclassTest{publicstaticvoidmain(String[]args){Scannersc=newScanner(Syst

importjava.awt.*;importjava.applet.*;importjava.util.*;publicclassdrawTestextendsApplet{publicvoidpa

1.抽象形状类packagecom;//抽象的形状类publicabstractclassShape{}2.显示接口packagecom;//接口publicinterfaceIDisplay{vo

packagetest;publicclassTest{publicstaticvoidmain(Stringargs[]){System.out.println(getSum(123));}publ

你好好看看Math相关的api