编写一个方法printarea,通过输入一个圆的半径显示圆的面积
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importjava.io.BufferedReader;importjava.io.InputStreamReader;publicclasstest{publicstaticvoidmain(St
1.思路:用一个字符串数组储存输入的数据,并分别输出。程序:Vara:array[1..3]ofstring;i:integer;BeginFori:=1to3doReadln(a[i]);Fori:
voidfun(intm,intn){for(inti=m;i
%输入一个数据后回车,接着输入第二个数据fprintf('请输入24个X的值(输入一个数据后回车)\n');for i=1:24  
programa4;vara,b,c:integer;beginreadln(a,b,c);if(((a>0)and(b>0)and(c>0))and((a+b>c)and(a+c>b)and(b+c
#includemain(){inti,j,k;printf("请输入数字\n");scanf("%d",&i);for(j=1;j
publicclassTest{publicstaticvoidmain(String[]args){System.out.println("圆的面积:"+area(2));System.out.pr
classMyMath{intlow,high;MyMath(inth){this(1,h);}MyMath(intl,inth){low=l;high=h;}intsum(){return(low+
这个可以这样做~cleara=rand(10,1);%产生一组随机数b=rand(10,1);%产生另一组随机数b=b-(dot(a,b)/dot(a,a)).*a;%可以使用施密特正交化的方法转化d
public class Test {\x09public static double area(double length,do
-------------------------------------文件1:Person.java--------------------------------------packagemya
#includevoidmain(){inta,b,c,t;int*pa,*pb,*pc;pa=&a;pb=&b;pc=&c;scanf("%d%d%d",pa,pb,pc);if(*pa>*pb){
varn,i,min,max,maxi,mini,s:integer;x:array[1..100]ofinteger;ans:real;beginreadln(n);fori:=1tondoread
08电商的同学,报上姓名,把分给我吧,不然.罚你把这题目抄100遍.chai
#includeintmain(){inta[4][4]={{7,4,3,2},{8,6,5,7},{3,7,2,5},{4,8,6,5}};inti,sum=0;for(i=0;i{sum+=a[i
pt = {2, 2};ContourPlot[ Sqrt[(x - pt[[1]])^2 + (y -&nb
/>vart;varl=prompt('请输入边长',3.5);t=3.1415926*(l/2.0)*(l/2.0);document.write("边长:"+l);document.write("
usingSystem;usingSystem.Text;namespaceMynamespace{publicclassProgram{publicstaticintmain(){inttemp=0
1:symsabRspRsdR这一句去掉就可以了.function[Rp,Rd,R]=aa11(a,b)N=[sqrt(51),sqrt(21.8);sqrt(2.3),sqrt(48.5)];N1=
importjava.awt.*; importjava.awt.event.*; importjavax.swing.*; publicclass计算器extendsJFrameimpleme