编写一个求圆面积的函数Area,
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 11:52:45
#include#definePI3.1415926doublearea(doubler){returnPI*r*r;}doubleperimeter(doubler){return2*PI*r;}i
#include#includeusingnamespacestd;classRectangle:publicShape{floatx1,x2,y1,y2;public:Rectangle(float
#definePI3.14#includeusingnamespacestd;doublearea(floati){return(PI*i*i);}doublecircumference(floati
第一个空,函数需要返回一个double类型的值,因此填:returna;第二个空,需要对a=5用area函数,因此填:area(a)最后这是一个C语言的问题,如果在计算机分类上问应该很快就解决了吧.
函数定义名Area,参数rFunctionArea(r)Area=3.1415926*r*rEndFunction调用例子:PrivateSubCommand1_Click()Label1.Capti
什么语言?给你个C#的,根据你需要的语言,改动一下privatedoublemiji(doublebanjing){doublepi=3.14;returnpi*banjing*banjing;}再问
#include<stdio.h>#include<stdlib.h>#define Pi 3.14159double square(double
classTrapezoid:publicShape{private:\x05doubletop;\x05doublebottom;\x05doubleheight;public:\x05Trapez
classTrapezoid:publicShape{private:doubletop;doublebottom;doubleheight;public:Trapezoid(doublet,
#include <stdio.h>float area(float r){ return 3.14159 *&nb
#include<stdio.h>#define Pi 3.14159double Square(double r){ &nb
include#include#defineS(a+b+c)/2#defineAREA(a,b,c)sqrt(S*(S-a)*(S-b)*(S-c))main(){floata,b,c;printf(
p=1/4*(2*x*z+y*y-x*x-z*z);应该改为p=1.0/4*(2*x*z+y*y-x*x-z*z);或者p=1/4.0*(2*x*z+y*y-x*x-z*z);原因是:当进行运算时,1
Console.WriteLine("请输入圆的半径");intr=int.Parse(Console.ReadLine());doublecircle=2*3.14*r;doublearea=3.1
1.functions=mianji(r)s=pi*r*r;end2.functionl=zhouchang(r)l=2*pi*r;end
voids(folata,folatb,folatc){folatp;p=(a+b+c)/2;S=√[p(p-a)(p-b)(p-c)];returns;}
publicinterfaceCircle{doublearea(doubler);}publicclassCircleImplimplementsCircle{publicdoublearea(do
//使用海伦公式#include/*ForIO*/#include/*Forsqrt()*/intmain(void){doublea,b,c,p,s;printf("请输入a,b和c:");scan
functionfun(d,h){if(d
利用海伦公式:S=(p(p-a)(p-b)(p-c))^(1/2);S为三角形面积,a,b,c为三角形三边长,p为三角形半周长(p=(a+b+c)*(1/2))(p(p-a)(p-b)(p-c))^(