编写程序,实现通过键盘输入x的值,求分段函数的值.
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voidswap(int*x,int*y){inttmp=*x;*x=*y;*y=tmp;}
#includeusingnamespacestd;doublefun(doublex){\x05if(x>-10&&x-5&&x5&&xx;\x05\x05cout再问:麻烦用C语言写一下再答:#i
voidmain(){intx,inty;printf("请输入X的值:");scanf("%d",&x);printf("\n");if(x
#include<stdio.h>int f(int x ){\x09if ( x>0 )\x09\x09return&n
#includemain(){\x09inti,j,m,n,a[10];\x09printf("请输入10个整数:\n");\x09for(i=0;i
#include "stdio.h"void main(){ int n,sum=0; printf(&q
#includeusingnamespacestd;boolIsPrime(intn){if(n
longpower(intm,intn){doublep=1;if(n>0){p=m*power(m,(n-1));returnp;}}voidmain(){intm,n;longk;scanf("%
/>程序一为:#include<iostream.h>voidmain(){\x09inta,b,c,s;\x09cout<<"请输入两个整数:";\x09cin>>
自己敲的,你看看是不是你要的……我吃饭去了,有事发邮件479292539@qq.com#include#defineM4#defineN5voidmain(){inta[M][N],i,j;intnu
#includemain(){charx,y,z;printf("请输入两个字符:");scanf("%c%c",&x,&y);z=x;x=y;y=z;//交换成功.}
scanf("%*4c%s",a);//a是字符数组,前4个字符省略不赋值printf("%c",a[0]);
#includevoidmain(){floata,x,z;scanf("%f,%f",&a,&x);printf("pleaseinputa,x:,.\n");z=1.0/2*(a*x+(a+x)/
if(x>0)y=-1;elseif(x
#includeusingnamespacestd;voidmain(){coutx;if(x
题目没说清楚,是x与n的乘积,还是x的n次方再问:是X的n次方再答:input"请输入x的值:"toxinput"请输入n的值:"tonk=1he=0dowhilk
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不知道你需要用什么语言,我就用C++给你写好了.#includeusingnamespacestd;intmain(){doublex;cin>>x;doubley;if(x=3&&x
#include#includevoidmain(){intn=0;inti=0;longsum=1;scanf("%d\n",&n);for(i=1;i
#includevoidmain(){intx,y;scanf("%f",&x);if(x=10){y=3*x-11;printf("%f",y);}else{y=2*x-1;printf("%f",