编写程序,读取在1到100-搜答案-智慧作业帮

#include<stdio.h>intmain(){ printf("%d",count(100)); &nb

intmain（void）｛inti,ans;For(i=1;i再答：��ټ�һ��#include再问：лл

////////////////////下面是whileintsum=0;int_i=0;while(_i

iTot=0Fori=1To100IfiMod5=0OriMod7=0TheniTot=iTot+iNextiPrintiTot结果是:1680【由于字数限制,去除了Sub,及变量定义】

#includevoidmain(){intsum=0;for(inti=1;i

PublicSubqqqqq()DimiAsIntegerDimjAsIntegerDimsAsIntegerDimCAsBooleans=0Fori=2To100C=FalseForj=2Toi-1

#includevoidmain(){inti,j=0;for(i=1;i

dimiaslongdimsumaslongsum=0fori=1to100step2sum=sum+inextiprintsum

下面程序是根据原理写的,已经调试成功.#include#includeintmain(){inti,flag[101];for(i=2;i

#include#includeintmain(){\x09inti,j;\x09unsignedseed;\x09inta[101];\x09printf("pleaseinputseed");\x

intsum=0;for(inti=0;i{if(i%3!=0){sum+=i;}}

用C++语言么?那应该很简单for(inti=1;icout

输出1-100间能被3整除的奇数

importjava.util.Scanner;publicclasstest{publicstaticvoidmain(String[]args){Scannerinput=newScanner(S

System.out.println(1+""+2+""+3+""+4);System.out.print(1+"");System.out.print(2+"");System.out.print(

1.过滤这100个数将这100个数中出现了多少个不重复的数字放入一个数组2.循环这个数组,循环取出里面的数,计算出此数在原数组中也就是之前生成的100个数中出现多少次你就这么实现吧,很简单两层的for

for(intx=0;xinta=input.nextInt();\x09\x09while(a!=0){\x09\x09num[i]=a;\x09\x09i++;\x09\x09a=input.ne

1(1)FileInputStream(2)charbuf;(3)(char)fis1.read()(4)while((buf=(char)fis2.read())>0)System.out.prin

PrivateSubCommand1_Click()s=0zf=0Fori=1To10s=InputBox("第"&i&"位评委给分:")zf=zf+sNextiPrint"总得分："&zfEndSu

//写入的不是ASCII码所以打开a.txt是乱码#include#include#includevoidmain(){FILE*fp1,*fp2;if((fp1=fopen("a.txt","w