编写程序,输出200-300之间所有能同时被3和5整除的数,并统计其个数
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static void Main(string[] args) { 
C源程序:#include"stdio.h"voidmain(){intn=6;inti,j;for(i=0;i
#include"stdio.h"voidmain(){inti,j;printf("");for(i=1;i
两句代码就够了:>> A=100:200;>> A(mod(A,3)~=0)ans = Columns 1&nbs
#includeintmain(){intn=5;inti=0;for(;i再问:for(;i
scanf("%d,%d,%d,&a,&b,&c");改成scanf("%d,%d,%d“,&a,&b,&c);printf("thelargerstnumberis%d\n,max");改成prin
PrivateSubCommand1_Click()Fori=1To100Forj=1ToiFork=1TojIfi^2=j^2+k^2ThenPrinti;j;kNextkNextjNextiEnd
classMAXn{publicstaticvoidmain(Stringargs[]){intk=1,sum=0;while((sum+=k)
#include "stdio.h"#define ROW 14#define COL 12int main(){ch
//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){inti,j;for(i=0;i
#include<iostream>using namespace std;int main(void){ int line,i,j;&n
#includemain(){inti,j,k,n;printf("请输入需要打印的图形的行数:");scanf("%d",&n);for(i=1;ii;j--)printf("");for(k=0;
#includeintmain(){\x09intn;\x09printf("请输入一个金字塔的行数(1-13):");\x09scanf("%d",&n);\x09voiddraw(intn);//
PrivateSubCommand1_Click()Fori=1To15Step2IfiPrintSpace((7-i));String(i,"*")ElsePrintSpace(i-9);Strin
c语言写的,希望对你有用#includevoidmain(){inti=0;intj=0;intk=0;for(i=0;i
#includeintmain(){inti,j,n=4;for(i=0;ifor(j=0;j
intSmallerThan=5;for(inti=1;i
楼主要用什么语言写啊C还是C++再问:C语言再答:#includevoidmain(){inti,j;for(i=0;i
publicclassTest{publicstaticvoidmain(String[]args){for(inti=1;i
#includeintmain(){charc='A';inti,j;for(i=0;i