编写递归函数计算给定的自然数n的各位数字之和

#includeintdigit(intn,intk){returnk>1digit(n/10,k-1):n%10;}intmain(){printf("%d",digit(12345,3));}

#includelongintfn(int);voidmain(){printf("%d",fn(10));}longintfn(intm){longinttemp;if((1==m)|(2==m))

很高兴回答你的问题!#includeintfun(intn,intx){if(n==0)return1;intmul=x;for(inti=n;i>1;i--)mul*=x;returnfun(n-1

longpower(intm,intn){doublep=1;if(n>0){p=m*power(m,(n-1));returnp;}}voidmain(){intm,n;longk;scanf("%

main{inti=2,n,s=0;printf("请输入n：")；scanf（“d%”,&n）；for（i

publicf(byvalnasinteger)aslongifn=1thenf=1elsef=f(n-1)+nendifendfunction

#includeintFibonacci(intn){if(n==1||n==2)//递归结束的条件,求前两项return1;elsereturnFibonacci(n-1)+Fibonacci(n-

#includelongfac(intn){inti;longx=1;for(i=2;i再问：谢谢咯！可是我说的是递归法哦！再答：#includelongfac(intn){if(n==0)retur

publicclassA{publicstaticvoidmain(Stringargs[]){intn=9;//任意自然数System.out.println(f(n));}publicintf(i

如果是要求前N个偶数之和：#includeusingnamespacestd;longFunctionadd(intn){longsum=0;for(inti=0;i

importjava.util.Scanner;publicclassOushu{Oushu(){try{System.out.println("请输入n值");Scannerin=newScanne

#include <stdio.h>char* dg(char* instr, char* outstr, char* 

程序已经调试过了,你看下吧,可以的话给个好评#include"iostream"usingnamespacestd;floatpower(floata,intn){if(n==1)returna;el

C描述functionttt(n){ returnn>1?n*ttt(n-1):1;}使用方法:ttt(21);

1.#include"stdio.h"//#defineRECURSION1#ifdefRECURSIONlongfact(intn){if(n

#includemain(){intn,i,j,k;while(scanf("%d",&n)==1){if(n==1||n==2){printf("%d\n",1);cont

if(n==1)\x05\x05return1;你可以改成n==0或者改成returnx取其中一种就可以了

#includedoublef(doublex,intn){if(n==1)returnx;else{doubled=1.0;inti;for(i=1;i

intfun(intn){inti,m=1;for(i=1;i

/*请输入行、列数为：34请输入数组3×4：123456789101112  1  2  3  4