编程:输入4*4的数组,求出对角线上行,列下标均为偶数的各元素的积
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#includevoidmain(){inti,max,min,a[]={8,2,5,-3,7,-9,0,-4,10,15};max=min=a[0];for(i=0;i
#includemain(){inta,b,c,d,max,min;scanf("%d,%d,%d,%d",&a,&b,&c,&d);max=a;min=a;if(b>max)max=b;if(c>m
#include/*定义一个5×4的二维数组,完成对数组的各元素的输入后.要求(1)求各行元素之和,并将这些和按从小到大排列输出.(2)求各列元素之和,并将这些和按从大到小排列输出.(3)对所有元素按
PrivateSubCommand1_Click()Dima#,b#,c#,p#Me.AutoRedraw=Truea=3:b=4:c=5Doa=Val(InputBox("请输入三角形第一条边","
你可以将行列算出的值用一个数组接收,这里是采用变量接收的方式.Option Compare DatabasePrivate Sub aa()Dim h
//prob.cpp:Definestheentrypointfortheconsoleapplication.//#include"stdafx.h"#include//#includeusingn
#include <iostream>#include <string>#define M 4#define N 4
#includevoidprint(intn[5][5]){inti,j;for(i=0;i{for(j=0;j{printf("%d\t",n[i][j]);}printf("\n");}}void
intfunc(int*a;intb)//这里a表示数组名,b表示数组的元素个数{intc=0;inti;for(i=0;i
题:#include<iostream>usingnamespacestd;intmain(){doubles1[2][3];doubles2[3][2];inti,j;for(i=0;i
char*s[12]={"Jan.","Feb.","Mar.","Apr.","May.","Jun.","Jul.","Aug.","Sep.","Oct.","Nov.","Dec."};int
#includeintmain(void){voidmax(int*);voidmin(int*);intarr[4][5];inti,j;for(i=0;i再问:能帮我看一下我的代码哪里错了吗,谢谢
你这个是转置吗?先输入一个矩阵Am*n阶的,转置里面应先初始化一个矩阵Bn*m的记得要先初始化哦!然后利用for循环两层i,jfori=0:n-1forj=0:m-1B(i,j)=B(j,i);然后就
#include<stdio.h>intmain(void){ inti,j,k; inta[10]; intmin=0,max=0; for(i=
#includeintmain(intargc,char*argv[]){inti,j,a[4][4],sum=0,p=1,max,maxi;for(i=0;i再问:请问intargc,char*ar
PrivateSubForm_Load()DimaAsInteger,bAsInteger,cAsInteger,MaxAsInteger,MinAsIntegera=InputBox("请输入a值"
#includemain(){intarray[3][4];inti,j,max;for(i=0;i
#includeintmain(){inta[4][4];for(inti=0;i
usingSystem;classProgram{staticvoidMain(string[]args){int[,]array=newint[5,5];inti,j,k;intmax,min,ma
#includevoidtest(){doublea[]={1,2,3,4,5,6,7,8,9,10,11,12};double*b=newdouble[3*4];for(inti=0;i再问:能改成