编程判断用户输入的三位正整数是否为水仙花数
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/03 04:31:08
DimXAsInteger这句出的毛病.你直接把它定义成整数型变量,输入3.5直接四舍五入转换为4.把它换成DimXAsSingle
#includeintmain(){intm[10],i,j=0,k;longn;scanf("%ld",&n);k=n;while(k>0){k/=10;j++;}i=j;while(i--){m[
#includeintmain(){inti;voidfun(inta);printf("输入数字:");scanf("%d",&i);fun(i);return0;}voidfun(inta){if
算法一:#includemain(){intn1,n2,gcd=1,k=2;scanf("%d%d",&n1,&n2);while(k0;i--)if(n1%i==0&&n2%i==0)printf(
#include#includeintmain(){printf("请输入一个正整数:");intn1,n2;boolflag1=false,flag2=false;scanf("%d",&n1);n
X一直不变,不就成死循环了吗.
#include"stdio.h"intmain(){\x09intn;\x09scanf("%d",&n);\x09if(n%7==0||n%5==0)\x09{\x09\x09printf("ye
饭要一口一口吃,作业要自己做
#include <stdio.h>#include <math.h>int main(void){  
#includeintmain(){intnum;inta;//百位intb;//十位intc;//个位scanf("%d",&num);a=num/100;//默认强制转为整型b=(int)(num
PrivateSubCommandButton1_Click()DimnNumAsLongIfIsNumeric(TextBox1.Text)ThennNum=Val(TextBox1.Text)If
//提示:153370371407是水仙花数#includevoidmain(){inti,j,k,n;printf("请输入一个三位整数\n");scanf("%d",&n);i=n/100;/*分
//看好记事本写的Judge.javapublicclassJudge{publicstaticvoidmain(String[]args){try{if(args.length!=3){Sy
#include<stdio.h>main(){ int ia; scanf("%d",&ia); if(ia%5==0
PHP代码:$number=25;//随便写了个数.if($number%5==0&&$number%7==0){echo'yes';}else{echo'no';}就是判断对5取余和对7取余等于0.
楼主你好,我帮你设计了一个,判断的是整数的位数,正负都可以,如果想小数的话,请另行通知.现在最大只能是9位代码如下#include"iostream"usingnamespacestd;intmain
VB语言吧,怎么跑到C/C++来了...代码如下:1、PrivateSubCommand1_Click()t=InputBox("请输入一个正数")t=tMod7SelectCasetCase0Pri
packageEx2_1;importjava.util.Scanner;classRectangle{publicstaticvoidmain(Stringargs[]){doublelength,
有时间和空间要求么?简单方法如下:count=0;for(i=A;i再问:你的好像不行,这是我写的,看看怎么改一下#include#includeintmain(void){intA,B,count=
main(){intd;scanf("%d",&d);if((d%3)||(d%8){printf("no!\n");}elseprintf("yes!\n");}再问:我编写了,好像此处if((d%