编程求fibonacci数列前28项的和
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/04 14:17:00
PrivateSubForm_Click()Dima(1To40)AsLongFori=1To40Ifi=1Ori=2Thena(i)=1Elsea(i)=a(i-2)+a(i-1)EndIfPrin
#includeintFibonacci(intn){if(n==0)return1;elseif(n==1)return1;elsereturnFibonacci(n-2)+Fibonacci(n-
#includevoidmain(){inta[40],i;a[0]=a[1]=1;for(i=2;i
PrivateSubForm_Click()DimnAsIntegern=Val(InputBox("请输入N:"))Dima,bAsLonga=1:b=1Fori=1TonPrinta&""&b&"
#include#include#includeusingnamespacestd;#defineM100inta[M];voidmain(){inti,j;a[0]=1;a[1]=2;i=1;
OptionExplicitDimf(40)AsLongPrivateSubCommand1_Click()DimiAsByteDimsAsLongf(1)=1f(2)=1s=2Print"No1:"
#include#defineN20//N可配,可改成前任意项intmain(void){intFibo[N];Fibo[0]=1;Fibo[1]=2;for(inti=2;i
#include#defineCOL10//一行输出10个longscan(){//输入求fibonacci函数的第N项intn;printf("InputtheN=");scanf("%d",&n)
非递归:staticvoidf(intn){longp1=1,p2=1,p=1;for(inti=1;i
#includevoidmain(){longf,f1,f2;inti;f1=1;f2=1;printf("%10d%10d",f1,f2);//每个数之间有点距离for(i=3;i
写一函数intFibonacci(intn){if(n==1||n==2){return1;}returnFibonacci(n-1)+Fibonacci(n-2);}
用递归多好啊,我用的递归,你参考一下!#includeusingnamespacestd;intfib(intn){if(n==0||n==1)return1;returnfib(n-1)+fib(n
Private Sub Form_Load()Dim I As IntegerForm1.AutoRedraw = TrueFor
#!/bin/bash#fibo.sh:Fibonaccisequence(recursive)#Author:M.Cooper#License:GPL3######----------algorit
我给你代码:#include <stdio.h>#include <stdlib.h>#define N 47int fibo
#includeintFib(intm){if(m==1||m==2)return1;returnFib(m-1)+Fib(m-2);}voidmain(){intn,i;printf("请输入n的值
publicclassFibonacci1{publicstaticlongfib(intn){longf1=1,f2=1;longm=0;if(n
#includevoidmain(){inta[20];int*p=a;*p=0;*(p+1)=1;for(inti=2;i
下面的程序可以修改宏定义N的值来确定输出的数的个数#include#defineN30voidmain(){unsignedlonginta[N];inti,j;a[0]=1;a[1]=1;for(i