编程题假设从键盘输入从某日午夜零点-搜答案-智慧作业帮

floatmax(floata[])//求数组a中的最大值函数{floatmax=0;for(inti=0;imax)max=a[i];//将数组a中比max大的元素存入max中returnmax;}

#includemain(){intm,n,k,j,s,t;printf("pleaseinputthenumberofm,n,k\n");scanf("%d",&m);scanf("%d",&n);

intn,sum=0;cin>>n;for(inti=1;i

判断是否存在《=0的值找出最大数判断两边之和大于第三边两边之差小于第三边（a==b）==c 是错误的判断想（a==b）返回的是1或者0 在判断==c肯定是错

#include <stdio.h>int main(){ char c; &

什么报错?再问：就只有这个Cpp12.obj-1error(s),0warning(s)再答：你看下那个错误具体是什么，写一下。再问：--------------------Configuration

题目2：#includevoidmain(){inta,b;printf("将237转换成小时和分钟输出\n");a=237/60;b=237%60;printf("hour:%d\nmin

#includevoidmain(){\x09intnum[100];\x09inti;\x09for(i=0;i

#include"stdio.h"//voidmain(void){inta,b,c;printf("请输入两个十进制整数!\na=");scanf("%d",&a);printf("b=")

楼主你好!根据你要求实现如下#include<stdio.h>int fun(int n){ if(n>0)return n*fun(n-1)

#includeintmax(intn);voidmain(){inta,b;printf("Pleaseinputnumber,endof-1:");scanf("%d",&a);while(a!=

#include "stdio.h"#define N 10void main(){ int a[N],ave,sum=

1.#include<stdio.h>intmain(void){inta,b,c;scanf("%d%d%d",&a,&b,&c);if(a+b<=c||a

#includevoidmain(){\x09inta;\x09scanf("%d",&a);\x09printf("%d*%d=%d\n",a,a,a*a);}//运行情况：33*3=9请按任意键继

#includeintmain(){inta,b,c;intmin,max;scanf("%d%d%d",&a,&b,&c);if(amax)max=c;printf("%d%d%d",max,a+b

#includevoidmain(){inti,j,n;printf("请输入n的值：\n");scanf_s("%d",&n);for(i=1;i

#includeintk;voidshow(){chara;printf("Pleaseinputtheletter.\n");scanf("\n%c",&a);printf("Theletter's

intmain(){intn=0;inti=0;intsum=0;scanf("%d",&n);for(i=2;i

#includevoidmain(){intn;sacnf("%d",&n);if(n%27==0)printf("Yes\n");elseprintf("No\n");}

编程题 假设从键盘输入从某日午夜零点