若2m=3,4n=8,则2的3m 2n-1次方-搜答案-智慧作业帮

｜M-N+2｜+(M+N-4)=0｜M-N+2｜=0M-N+2=0N=M+2M+N-4=0N=4-MM+2=4-MM=1N=1+2=3

m+2n=2,.(1)3m+4n=8.(2)(2)-(1)*2:m=4n==(2-4)/2=-1

既然是相反数,就是m和n两者加起来为0的,例如-1和1,-2和2就互为相反数,所以这里答案是0咯

解|m-n|+(m+2n-3)²=0∴m-n=0①m+2n-3=0②∴m=n将m=n代入②得：3n-3=0∴n=m=1∴m+n=1+1=2

m-n=2.1/2(m-2n+3)=3求出m和n代人

n/m=3/4m/(m+n)=1/[1+n/m]=4/7n/(m-n)=1/[m/n-1]=3m^2/(m^2-n^2)=1/[1-n^2/m^2]=16/7所以原式=9/7当然,你可以通分来算,也能

m+2n=2,.(1)3m+4n=8.(2)(1)*2:2m+4n=4.(3)(2)-(3):m=44+2n=2n=-1m+n=4-1=3

m+2n=2且3m+4n=8,求m+n

m+2n=2且3m+4n=8所以(3m+4n)-(m+2n)=8-23m+4n-m-2n=62m+2n=62(m+n)=6m+n=3

(m-2n)/(2m+n)=3m-2n=6m+3n5m+5n=0m=-n[3(m-2n)/(2m+n)-(m-2n)/[2(2m+n)]-{9(m-2n)/[4(2m+n)]}=[3(-n-2n)/(

1/M=1/[√(n+4)-√(n+3)]=[√(n+4)+√(n+3)]/[√(n+4)+√(n+3)][√(n+4)-√(n+3)]=[√(n+4)+√(n+3)]/[(n+4)-(n+3)]=√

m/(m+n)+n/(m-n)-n^2/(m^2-n^2)=[m(m-n)+n(m+n)-n^2]/(m^2-n^2)=m^2/(m^2-n^2)=1/(1-(n/m)^2)=1/(1-(3/2)^2

若（m-4）的2次方+|n+3|=0,则m=?,n=?∵（m-4）²和|n+3|都是非负数∴（m-4）²=0则|n+3|=0所以m=4n=-3

M-2=0N+3=0M=2N=-3N的M次方=9

(2m-n)/(m+2n)=5∴(m+2n)/(2m-n)=1/5∴3(2m-n）/m+2n-m+2n/2m-n+3=3×(2m-n)/(m+2n)+(m+2n)/(2m-n)+3=15+1/5+3=

题错了应该是m^3-m^2n-mn^2+n^3=m^3+n^3-mn(m+n)=m^3+n^3-0=(m+n)(m^2-mn+n^2)=0

6m（m-n）-4n（n-m）=6m3+4n（m-n）=18m+4×3n=6×（3m+2n）=6×2=12

(8^m)*(n^4)=(2^(3m))*(2^(2n))=2^(3m+2n)=2^3=8

4^m*8^n=2^2m*2^3n=2^(2m+3n)=2^5=32再问：1/4^2006*2^4010，会吗？要过程再答：1/4^2006*2^4010=1/4*1/4^2005*4^2005=1/

2m+n分之m-2n=3所以原式=(3+1/3-5/4)[2m+n分之m-2n=3]=25/12×3=25/4

∵|m-n|=n-m=-(m-n)∴m-n