若m的平方加m减0等于0
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m²+2m+1=0(m+1)²=0m+1=0m=-1所以m²+1/m²=1+1=2
解题思路:利用完全平方公式解答解题过程:请看附件最终答案:略
根据M?軲-1=0,推出M?鯩=1M?009=M?009=M(M?∕)+M?009=M?㎝+2009=1+2009=2010
m²+m-1=0则:m²+m=1又:m³+2m²+2012=(m³+m²)+m²+2012=m(m²+m)+m²
m^3+2*m^2+2007=m*(m^2+m-1)+m^2+m-1+1+2007=2008
m^2+m-1=0m^3+2m^2+2009=(m+1)(m^2+m-1)+2010=2010
m^2+2m-1=0求m^2+(1/m)^2所以m!=0由已知得m+2-1/m=0m^2+(1/m)^2=(m-1/m)^2+2=4+2=6
因为:m^2+m-1=0所以,乘以m得到:m^3+m^2=mm^3+2m^2+2011=m^2+m+2011=1+2011=2012
m^2-3m+1=0m-3+1/m=0m+1/m=3(m+1/m)^2=9m^2+2+1/m^2=9m^2+1/m^2=7
m^2+m-1=0m^2+m=1m^3+2m^2+2002=m(m^2+m)+m^2+2002=m+m^2+2002=2003
㎡+n²+4m-6n+13=0㎡+4m+4+n²-6n+9=0(m+2)²+(n-3)²=0m=-2n=3(-2)³=-8再问:已知a减b等于5,ab
∵m²+m-1=0∴m(m²+m-1)=m³+m²-m=0,即m³+m²=m∴m³+2m²+2004=m+m²
m²-4n²=6(m-2n)(m+2n)=6m-2n-2=0m-2n=2m+2n=3
(m+1)方+(n-3)方=0m=-1n=3m+n=2
置换法.m-5m-1=0m-5m=1m-1=5m因为m≠0,两边同时除以m得m-1/m=5m+1/m=(m-1/m)+2m*1/m=25+2=27所以2m-5m+1/m=m-5m+m+1/m=1+27
若M的平方加M减1等于0,则M的立方加2M的平方加2012=(M的平方+M-1)(M+1)+2013=0+2013=2013
m³-3m²+3m-2=m³-m²+m-2-2m²+2m=m(m²-m+1)-2(m²-m+1)=0+0=0
m^2+n^2-10m+6n+34=0(m^2-10m+25)+(n^2+6n+9)=0(m-5)^2+(n+3)^2=0m=5n=-3