MN转换N
来源:学生作业帮助网 编辑:作业帮 时间:2024/10/01 10:04:28
由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m
m²n-mn²;=mn(m-n)5m²n²这个分不了了分子5m²n²分母mn(m-n)可以约去mn分子剩下:5mn分母剩下:(m-n)
同学,你题目应该是写错了应该是这样的吧mxm+mn+m=14nxn+mn+n=28两列相加,得mxm+nxn+2mn+m+n=42得(m+n)(m+n)+m+n=42得m+n=6或m+n=-7
3m-5mn+3n/(-m)+3mn-n=【3(m+n)-5mn】/【3mn-(m+n)】=【3-5mn/(m+n)】/【3mn/(m+n)-1】=【3-5x2】/【3x2-1】=-7/5
答:mn/(m+n)=2分子分母同除以mn得:1/(1/n+1/m)=21/m+1/n=1/2(3m-5mn+3n)/(-m+3mn-n)分子分母同除以mn得:=(3/n-5+3/m)/(-1/n+3
再答:谢谢
由于:mn/(m+n)=2则有:mn=2(m+n)则:原式=(3m+3n-5mn)/(-m-n+3mn)=[3(m+n)-5mn]/[-(m+n)+3mn]=[3(m+n)-10(m+n)]/[-(m
因为m-mn=21,mn-n=15,所以:m-n=(m-mn)+(mn-n)=21+15=36m-2mn+n=(m-mn)-(mn-n)=21-15=6希望能都帮到你,追问:对不起啊.我把题发错了,m
-MN(M^2N^5-MN^3-N)=-(-6)^3+(-6)^2-(-6)=258
m/(m-n)-n/(m+n)+mn/(m^2-n^2)=[m(m+n)-n(m-n)]/(m+n)(m-n)+mn/(m+n)(m-n)=(m^2+mn-mn+n^2)/(m+n)(m-n)+mn/
mn(m-n)-(n-m)=mn(m-n)+(m-n)=(mn+1)(m-n)
原式=(m²+2mn+n²-4mn)(m²-2mn+n²+4mn)+2m²n²=(m²-2mn+n²)(m²+
原式=-2mn+2m+3n-3mn-2n+2n-m-4n-mn=-6mn+m-n=-6×2+4=-8
=(m^2-mn)+2(m^2-n^2)=(m^2-mn)+2(m^2-mn)+2(mn-n^2)题目条件打错了,自己代入一下
m²n(m-n)-4mn(n-m)=m²n(m-n)+4mn(m-n)=mn(m+4)(m-n)
2[mn+(-3m)]-3(2n-mn)=2mn-6m-6n+3mn=5mn-6m-6n=5mn-6(m+n)m+n=2mn=-3=-15-12=-27
原式=3m^2-3mn+6n^2-2mn+2m^2-2n^2+5mn-4n^2+1=5m^2+1再问:(2x-3y+z)-3(x-2(-z+(x-y))-(3y-5z)再答:原式=2x-3y+z-3(
3(m^2n+mn)-4(mn-2m^2n)+mn.=3m^2n+3mn-4mn+8m^2n+mn.=11m^2n.
-9mn(m-3n+2)