解方程1 x² 3x 2加1 x² 5x 6加1 x² 7x 12=1 x 4
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x
后面的x²+11x-708有误吧!再问:没有题目就这样能不能帮我再答:那我就试试:原式为:1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
x+2/x+1-x+4/x+3=x+6/x+5-x+8/x+7(x+1+1)/(x+1)-(x+3+1)/(x+3)=(x+5+1)/(x+5)-(x+7+1)/(x+7)(x+1)/(x+1)+1/
3/x2=1/x2-x即3*2-3x=x*22x*2=3Xx=0(舍去)x=3/2
6/(x-1)+3/x=(x+5)/(x²-x)方程式两边都乘以x(x-1),分母不能等于0,即x≠0且x≠1得:6x+3(x-1)=x+5化简得:6x+3x-3=x+5,即8x=8得:x=
x^2-3x-1=0a=1b=-3 c=-1△=b^2-4ac=3^2-4*-1=13两个根为,所以X1=(3+根号13)/2 X2=(3-根号
方程两边同时乘以x(x+1)(x-1)得:5(x-1)+3(x+1)=7x解得:x=2检验:x(x+1)(x-1)=6所以x=2是原分式方程的解
(1)5x-16×3=102 5x-48=102  
令a=x2+x(a+1)(a+12)=42a2+13a+12=42a2+13a-30=0(a+15)(a-2)=0a=-15,a=2x2+x=-15x2+x+15=0无解x2+x=2x2+x-2=(x
7/(x+x2)-3/(x-x2)=6/(x2-1)两边同乘以x(x+1)(x-1),得7(x-1)+3(x+1)=6x7x-7+3x+3=6x10x-6x=3-74x=-4x=-1经检验x=-1是增
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31)x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得:(x²+x)²-1=3(x²+x)/22(x²+x)²-3
再答:这样再答:答案等于4/3颠倒一下我看错了再答:对不起啊
通分:(x^2-3x)+(2x-1)(x+1)=0化简:3x^2-2x-1=0x1=1(舍去,分母不为0)x2=-1/3
3x(x+2)+2(x-1)²=5(x²+8)3x²+6x+2(x²-2x+1)=5x²+403x²+6x+2x²-4x+2=5x
1+1/(x+2)+1+1/(x+3)=1+1/(x+4)+1+1/(x+1)1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1)1/(x+3)-1/(x+4)=1/(x+1)-1/(x+2