作业帮解方程:2(x 2)(x-1)-(x-3)(x 3)=(x-5)2
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设(x²-1)/(x²+2x)=t则8t+3/t=118t²-11t+3=0(8t-3)(t-1)=0解得t=3/8或t=11.t=3/8(x²-1)/(x&#
后面的x²＋11x－708有误吧!再问：没有题目就这样能不能帮我再答：那我就试试：原式为：1/x2+x+1/x2+3x+2+1/x2+5x+6+1/x2+7x+12+1/x2+9x+20=5
1.令t=x+1/x则t^2=x^2+1/x^2+2代入方程：2（t^2-2)-3t-1=02t^2-3t-5=0(2t-5)(t+1)=0t=5/2,-1当t=5/2时,由x+1/x=5/2得x=2
2/(x2-x)+6/(1-x2)=7/(x2+x)2/x(x-1)-6/(x-1)(x+1)=7/x(x+1)[x*(x-1)*(x+1)]*[2/x(x-1)-6/(x-1)(x+1)]=[7/x
原式可化为1/(x+1)(x-3)+2/(x-3)((x+2)+3/(x+1)(x+2)=0两边同乘以：(x+1)(x+2)(x-3)得：(x+2)+2(x+1)+3(x-3)=0(x≠-1,x≠-2
∵(x+1x)2＝x2+1x2+2，∴方程：2（x2+1x2）-3（x+1x）-1=0可化为2(x+1x)2−3(x+1x)−5＝0．因式分解为[2(x+1x)−5][(x+1x)+1]=0，∴2(x
令a=x2+x(a+1)(a+12)=42a2+13a+12=42a2+13a-30=0(a+15)(a-2)=0a=-15,a=2x2+x=-15x2+x+15=0无解x2+x=2x2+x-2=(x
令x²+x=t原方程变为t+1=6/tt²+t-6=0(t+3)(t-2)=0则t=2或-31）x²+x=2x²+x-2=0(x+2)(x-1)=0x=-2或x
2(x^2+1)/(x+1)+6(x+1)/(x^2+1)=72(x^2+1)^2+6(x+1)^2=7(x+1)(x^2+1)2(x^2+1)^2-7(x+1)(x^2+1)+6(x+1)^2=0[
x2+x+1=2/(x2+x)(X²+x)²+(x²+x)-2=0(x²+x+2)(x²+x-1)=0∴x²+x-1=0x=(-1±√5)/
两边乘x(x+1)(x-1)2(x-1)+3(x+1)=4x2x-2+3x+3=4x5x+1=4xx=-1经检验,x=-1时分母x+1=0增根,舍去方程无解
(x²+x)(x²+x-2)=-1把(x²+x)看成整体(x²+x)[(x²+x)-2]=-1运用乘法分配率(x²+x)²-2(x
x²+x-1/(x²+x)=3/2两边同时乘以(x²+x)得：(x²+x)²-1=3(x²+x)/22(x²+x)²-3
通分：(x^2-3x)+(2x-1)(x+1)=0化简：3x^2-2x-1=0x1=1(舍去,分母不为0)x2=-1/3
（x-4）/（x²+x-2）=1/(x-1)+(x-6)/(x²-4)(x-4)/(x-1)(x+2)=1/(x-1)+(x-6)/(x-2)(x+2)(x-4)(x-2)=(x-
x²－2x=2x＋1x²－4x=1x²－4x＋4=5(x－2)²=5x－2=±√5x=2±√5
2/x2=30=0x=±1/√15再问：过程再答：合并同类项1/x2+1/x2+1/x2+2x+11x-13x+10+10+10=03/x2+30=010x2+1=0x==±√10i/10刚才答案有误
把题拍过来帮你解
已知方程,然后x=±√7