解方程:2x-5分之x+5-2x分之5=1-搜答案-智慧作业帮

(x+2)分之(x+1)+(x+5)分之(x+4)=(x+3)分之(x+2)+(x+4)分之(x+3)x=-7/2再问：求过程正确答案是负2分之7我知道答案不知道过程再答：1/(2+x)+x/(2+x

1/x+1/(x+1)=5/2(x+1)左右两边乘以2x*(x+1)2(x+1)+2x=5xx=2

(x-1)/x-(1-x)/(x+1)=5(x-1)/2(x+1),(x-1)/x=5(x-1)/2(x+1)+(1-x)/(x+1)=(5/2-1)(x-1)/(x+1)=3(x-1)/2(x+1)

x+1分之x+2加上x+4分之x+5等于x+2分之x+3加上x+3分之x+4x+x/1+2+x+x/4+5=x+x/2+3+x+x/3+4x+x+2+x+x/4+5=x+x/2+3+x+x/3+4x+

1/{(x-1)(x-2)}=1/{(x-4)(x-5)}首先,分母不为零,∴x≠1,2,4,5通分：(x-4)(x-5)=(x-1)(x-2)x^2-9x+20=x^2-3x+26x=18x=3

x+1分之x+2减去x+3分之x+4=x+5分之x+6减去X+7分之x+8方程两边分别通分,得[(x+2)(x+3)-(x+1)(x+4)]/[(x+1)(x+3)]=[(x+6)(x+7)-(x+8

解分式方程输入很辛苦.经检验X=7/2是原方程的解.

由6x^2+5x+(6/x^2)+(5/x)=38移项,同时加上减去12再化简得到：6[x^2+2+(1/x^2)]+5[x+(1/x)]-50=0化简为：6[x+(1/x)]^2+5[x+(1/x)

-3,-1/3,0.5,2

两边同乘以（x^2+1）得5x+2=33(x+1)=33x+3327x=-31x=-31/27

原分式方程可变形为；5x+2/x(x+1)=3/x+1分式两边同乘公分母得：5x+2=3x解得：x=1检验：当x=1时,公分母x(x+1)不等于0所以x=1是原分式方程的解(/表示除号）再问：你算错啦

2x²/(x+1)-3(x+1)/x²=-5令a=x²/(x+1)2a-3/a=-52a²+5a-3=0(2a-1)(a+3)=0a=1/2,a=-3x

两边乘x(x-2)3x=5x-10x=5经检验,x=5是方程的解1/(x+3)+2/(x-3)=1/(x+3)(x-3)两边乘(x+3)(x-3)x-3+2x+6=1x=-2/3经检验,x=-2/3是

等号前后同时分别计算减法得：(x+1)(x+3)分之2=(x+5)(x+7)分之2所以：(x+1)(x+3)=(x+5)(x+7)x^2+4x+3=x^2+12x+35x=-4

x/(x-5)=(x-2)/(x-6)两边同乘惟(x-5)(x-6)x(x-6)=(x-2)(x-5)x^2-6x=x^2-7x+10x=10检验,代回到方程左边=10/(10-5)=2右边(10-2

x=123/14

化简3x/5+2x/5-3x/7=4/3x-3x/7=4/34x/7=4/3x=7/3

1+1/(x+2)+1+1/(x+3)=1+1/(x+4)+1+1/(x+1)1/(x+2)+1/(x+3)=1/(x+4)+1/(x+1)1/(x+3)-1/(x+4)=1/(x+1)-1/(x+2

x+2分之x+1-x+3分之x+2=x+6分之x+5-x+7分之x+61-（x+2）分之1-[1-（x+3）分之1]=1-(x+6)分之1-【1-(x+7)分之1】从而(x+3)分之1-(x+2)分之