解方程x-5 x²-1+1=3 x+1
来源:学生作业帮助网 编辑:作业帮 时间:2024/07/07 11:39:34
2(x-2)(x+3)-(2x-5)(x-1)=3x+72(x²+x-6)-(2x²-7x+5)=3x+72x²+2x-12-2x²+7x-5=3x+79x-1
4/(x-2)+(x-1)/[(x-2)(x-3)]-2/(x-3)=0[4(x-3)+(x-1)-2(x-2)]/[(x-2)(x-3)]=03(x-3)/[(x-2)(x-3)]=0不知道解了~~
x(2x-4)+3x(x-1)=5x(x-3)+82x²-4x+3x²-3x=5x²-15x+88x=8x=1
我给个思路吧(X+2-1/X+2)-(X+3-1/X+3)=(X+6-1/X+6)-(X+7-1/X+7)1-1/(X+2)-1+1/(X+3)=1-1/(X+6)-1+1/(X+7)剩下的就自己解决
是X/(X-2)-(1-X^2)/(X^2-5X+6)=2X/(X-3)吗?首先因式分解(X^2-5X+6)=(X-2)(X-3),显然X不等于2且X不等于3,所以等式两边同乘以(X-2)(X-3)得
(x-3)(x-2)-(x-4)(x-1))/((x-1)(x-2))=((x-5)(x-4)-(x-6)(x-3))/((x-3)(x-4))2/((x-1)(x-2))=2/((x-3)(x-4)
2x+4x+6x...+100x=1-(x+3x+5x+...+99x)x(2+4+6+...+100)=1-x(1+3+5+...99)x(2+4+6+...+100)+x(1+3+5+...+99
再答:字好不好看就别介意了嘛再问:...
x/(x-2)=2x/(x-3)+(1-x)/(x-5x+6)x/(x-2)=2x/(x-3)+(1-x)/(x-2)(x-3)x(x-3)/(x-2)(x-3)=2x(x-2)/(x-2)(x-3)
通分化简得到(x+1)(x+2)=(x+5)(x+6)3x+2=11x+308x=-28x=-7/2
两边乘x(x+3)(x-3)2x³+3x²--27x-x²-3x=5x³-45x-3x³+2x²+27x-18-27x-3x=-45x+27
首先由题意得x+1≠0,x+7≠0,x+5≠0,x+3≠0,即x≠-1,x≠-7,x≠-5,x≠-3,则先简化方程(x+1+1)/(x+1)+(x+7+1)/(x+7)=(x+5+1)/(x+5)+(
移项,把X项移到左边为3X,常数项移到右边为1,两边同时除以3得X=1/3
(1/x-7)+(1/x-1)=(1/x-6)+(1/x-2)1/(X-7)-1/(X-6)=1/(X-2)-1/(X-1)(X-6-X+7)/[(X-7)(X-6)]=(X-1-X+2)/[(X-1
请把分子或者是分母用括号括起来我好回答
这个展开就行了哇.2*(x^2+x-6)-(2*x^2-7X+5)-3x-7=0化简得:6X=24x=4应该是对的.嘿嘿.
(x+1)(x-3)=2x+5x²-2x-3=2x+5x²-4x=8x²-4x+4=8+4(x-2)²=12x-2=±2√3x=2-2√3,x=2+2√3
x(x+2)+(2x+1)(2x-1)=5(x²+3)x²+2x+4x²-1=5x²+152x=16x=8
设X为正数则:(X+2)-(3X+5)=1+X解得X=-4/3设X为负数则:(-X+2)-(-3X+5)=1+(-X)解得X=4/3