计算.(2ab)² b(1-3ab 4a²b)-搜答案-智慧作业帮

1/2(3a方-2ab+4b方）-2(3/4方-ab-3b方)=3/2a方-ab+2b方-3/2a方+2ab+6b方=ab+8b方=b(a+8b)

(a^3-4a^2b-a+4ab^2)/a(a-2b+1)=(a^2-4ab+4b^2-1)/(a-2b+1)=[(a-2b)^2-1]/(a-2b+1)=(a-2b+1)(a-2b-1)/(a-2b

哟工乘法分配律=1/8a^5b²+1/12a^4b²-1/4a³

2a^2×b^4-3(ab^2)^2=2a^2b^4-3a^2b^4=-a^2b^4

-（8a）2/45-2b=(21-b)2→-82a/45-2b=22(1-b)→-82a=41-b*45-2b→-64a=46-3b→-64a=642-b→a=b-2a+b=2(9a)b=(3b)a/

楼上的答案不一样是因为楼主你2分之1这个有歧义,如果只是a²前面有2分之1那答案就是3a²/2+6ab,如果是2分之1（A²+3AB-B²）,那么答案就是1.5

(-2ab)^3(5a^2b-1/2ab^2+1/4b^3)=-8a^3b^3(5a^2b-1/2ab^2+1/4b^3)=(-8a^3b^3)×(5a^2b)-(-8a^3b^3)×(1/2ab^2

答：a+b=-3ab=2所以：a和b都是负数所以：a/b>0,b/a>0(a+b)²=9a²+2ab+b²=9a²+b²+4=9a²+b&#

2/3a²-1/2ab+3/4a²+ab-b²=17/12a²+1/2ab-b²=1/12(17a²+6ab-12b²)

(a^2+3ab+b^2)(a^2-3ab+b^2)=[(a^2+2ab+b^2)+ab]*[(a^2-2ab+b^2-ab)]=[(a+b)^2+ab]*[(a-b)^2-ab]=(a+b)^2*(

原式=(ab(a-1)-(a-1))/(ab(b+3)-(b+3))÷((a+2)(a-1))/((b+3)(b-2))=(a-1)/(b+3)*((b+3)(b-2))/((a+2)(a-1))=(

(—3ab)(2a²—1/3ab+5b²)=-6a^3b+a^2b^2-15ab^3再问：能计算这个吗？(a+1/3)(a-1/4)再答：(a+1/3)(a-1/4)=a^2-a/

(-a^2b)^3-(a^3)^2b^3+(-a)^4*(ab)^2*(-2b)=-a^6b^3-a^6b^3+a^4*a^2b^2*(-2b)=-2a^6b^3-2a^6b^3=-4a^6b^3

(2ab^2)乘以（-3a^2b)^2=(2ab^2)乘以9a^4b^2=18a^5b^4

根号b/a+根号a/b=根号(b^2+a^2)/ab=根号[(a+b)^2-2ab]/ab因为a+b=-3,ab=2,所以=根号[(-3)^2-2*2]/2=根号（9-4）/2=根号5/2=（根号10

a+9b/3ab-a+3b/3ab=4/aa^2b^3/(2a^-1b^2)^-3=1/a^3b^2*b^3

3a·(-3b)^2·(-2ab)=3a·9b^2·(-2ab)=-54a^2·b^3x^ny·(-x^2y^n)=-x^(n+2)·y^(n+1)(2a+b)^2-(2a+b)(2a-b)=4a^2

5a^2b÷(-3分之1ab)×2ab^2=-30a^(2-1+1)b^(1-1+2)=-30a²b²

-a^4b^8

(-2a^3b^3c)(5ab^2)/(1/3a^3b^2)=(-10a^4b^5c)/(1/3a^3b^2)=-30ab^3c