计算:5x-3分之2x除25x方-9分之3乘5x 3分之x

(x-2)/(x+3)÷[x-3+5/(x+3)]=(x-2)/(x+3)÷[(x-3)(x+3)+5]/(x+3)=(x-2)/(x+3)÷[(x²-9+5)/(x+3)]=(x-2)/(

（x^2+3X+6）/(x^2+3X+2)=[(x+1)(x+2)+4]/[(x+1)(x+2)]=1+4/[(x+1)(x+2)](x^2+5X+2)/(x^2+5X+6)=[(x+2)(x+3)-

=1/(x-5)-6/(x+5)(x-5)-(x+1)/2(x+5)=2(x+5)/2(x+5)(x-5)-12/2(x+5)(x-5)-(x+1)(x-5)/2(x+5)(x-5)=(2x+10-1

另外一个是2除?还是除以?再问：不好意思，打漏一个字，是除以再答：再问：能不能详细的写出过程？我不是理解得很好。麻烦你啦再答：这就是详细的过程了，你是要我解释每步的原因吗？？因为第二题，我不知道你是：

原式=(x^2+3x)/(x^2+x-6)-(x+2)/(x^2-4)=x(x+3)/(x+3)*(x-2)-(x+2)/(x+2)*(x-2)=x/(x-2)-1/(x-2)=(x-1)/(x-2)

2/(x-3)=(1-x)/(3-x)-5,两边同乘以(x-3),得：2=-(1-x)-5(x-3),去括号,合并同类项,移项,得：4x=12,x=3.将x=3代入原方程检验,x-3=0,分母为0,分

原式=(x-1)²/2(x²-9)÷[-3(x-1)/4x(x-3)]=(x-1)²/2(x+3)(x-3)×[-4x(x-3)/3(x-1)]=-2x(x-1)/3(x

x→+∞时,lim[(2x²-3x+5)/(3x²+2x+4)]=lim[(2-3/x+5/x²)(3+2/x+4/x²)]=(2-0+0)/(3+0+0)=2

[(x+2)+1]/(x+2)-[(x+1)+1]/(x+1)=[(x+4)+1]/(x+4)-[(x+3)+1]/(x+3)1+1/(x+2)-1-1/(x+1)=1+1/(x+4)-1-1/(x+

=1/(x-5)-6/(x+5)(x-5)-(x+1)/2(x+5)=2(x+5)/2(x+5)(x-5)-12/2(x+5)(x-5)-(x+1)(x-5)/2(x+5)(x-5)=(2x+10-1

2x/(5x-3)除3/（25x²-9）乘x/(5x+3）=2x/(5x-3)×(5x+3)(5x-3)/3×x/(5x+3)=2x²/3通分x-y/(2x+2y)与xy/(x+y

不知道你题目是不是有问题这句话应该为(1/16)/(5x/12)=x/3整理x^2=9/20

原式=2x/(x^2-4)-1/(2-x)+3/(x+2)=2x/(x-2)(x+2)+1/(x-2)+3/(x+2)=[2x+(x+2)+3(x-2)]/(x-2)(x+2)=(6x-4)/(x-2

1.（4x^2-25y^2）/(2x-5y)=(2x+5y)(2x-5y)/(2x-5y)=2x+5y2.(2x^2-2x+1\2)/(x-1\2)=2(x^2-x+1/4)/(x-1/2)=2(x-

原式=[x/(x-3)]-[5x/(x²-x-6)]=[x/(x-3)]-(5x)/[(x-3)(x+2)]=[x(x+2)]/[(x-3)(x+2)]-(5x)/[(x-3)(x+2)]=

解原式=3(2-x)/3(x-4)(x+2)+(x+4)(x-4)/3(x+2)(x-4)=(6-3x)/3(x-4)(x+2)+(x²-16)/3(x+2)(x-4)=(6-3x+x

先分别把第1、2项合并,第3、4项合并,最后加总,原式=[(5x+10)-(3x-3)]/[(x^2+x)-2]-[(5x+15)-(3x-6)]/[(x^2+x)-6]=(2x+13)/[(x^2+

6X(-2)的3次方=6X（-8）=-48(-23)除(-3)X3分之一=（-23）X（-3分之一）X3分之一=九分之235X(-1)-(-4)X(-4分之1）=（-5）-1=-6（2分之1-4分之1

原式=[（x+2）/x（x-2）-（x-1）/（x-2）²]÷（4-x）/x=[（x+2）（x-2）/x（x-2）²-x（x-1）/x（x-2）²]÷（4-x）/x=[（