12X^3 12X^2 1=0
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x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)x/(2x+3)=(x+7)/(x-5)x(x-5)=(x+7)(2x+
这个函数是一个奇函数,当x>0时,-x
每四项为一组,第一组x+x*x+x*x*x+x*x*x*x=x(x+x*x+x*x*x)=0以此类推结果为〇
方程化为:6/(x+2)-(x+2)/(x-2)+x^2/(x+2)(x-2)=0两边同时乘以(x-2)(x+2)6(x-2)-(x+2)^2+x^2=06x-12-4x-4=02x=16x=8经检验
(X+X)+(X-X)+(X*X)+(X/X)=1002X+0+X*X+1=1002X+X*X=99X(X+2)=99X=9再问:请问X(X+2)=99解为什么就等于9了呢没看懂再答:换成算术法你就明
x³-2x²-5x²+4x+12=0x²(x-2)-(5x²-4x-12)=0x²(x-2)-(5x+6)(x-2)=0(x-2)(x&su
(x+1)(x+2)(x^2-2x-1)(x-3)(x-4)+24=0(x+1)(x-3)(x+2)(x-4)(x^2-2x-1)+24=0(x^2-2x-3)(x^2-2x-8)(x^2-2x-1)
题目应是1/(x^2+x﹚+1/(x^2+3x+2﹚+1/(x^2+5x+6﹚+1/(x^2+7x+12﹚=4/211/x(x+1﹚+1/(x+1)(x+2)+1/(x+2)(x+3)+1/(x+3)
x/(2x^2-11x-21)=(x+7)/(x^2-12x+35)x/(2x+3)(x-7)=(x+7)/(x-5)(x-7)约去x-7(显然x=7不是方程的根)x/(2x+3)=(x+7)/(x-
应该是-2x²,不是-3x²3x²-x=1原式=9x^4-3x³+15x³-5x²+3x²-7x+2001=3x²(3x
用求根公式,配方法
第一题.3x=126x=42第二题.2x=10.8x=5.4第三题6x=19.2x=3.2第四题5x=1.8x=0.36第五题3x=32-13.53x=18.5x=6.17(约等于)第六题x-8.1=
x^2+8x+12=0(x+6)(x+2)=0x+6=0x=-6x+2=0x=-2
x(1−21−x)÷(x+1)−x(x2−1)x2−2x+1=x[1−x−21−x•1x+1−(x−1)(x+1)(x−1)2]=x(1x−1−x+1x−1)=−x2x−1,∵x2+x-1=0,∴-x
=x^2+10x-24+x^2+15x+56-x^2+5x+50=x^2+30x+82=4+60+82=146其实,不化简,直接代入=14*0+9*10+7*8=0+90+56=146也很简单
1.3x乘x-7x+1=0x^2-7/3x=-1/3(x-7/6)^2=49/36-1/3x=7/6±√37/62.12x乘x-8x-21=0x^2-3/4x=7/4(x-3/8)^2=7/4+9/6
代进求根公式x=[-b±(b^2-4ac)^(1/2)]/2a,其中a=1,b=-7,c=-12.
3x²=10x+83x²-10x-8=0x=(10±√(100+4×3×8)/2*3x=(10±√196)/6x=(10±14)/6∴x1=4x2=-2/33x²-10x
1、任取x=a≤0,此时f(x)=a^2+a当x=-a>0时,f(x)=-a^2-a=-f(x)为奇函数2、f(x)+g(x)=1/(x-1)①,则f(-x)+g(-x)=1/(-x-1),再由两函数