输入n个实数存入一维数组,输出其中的最大值.最小值和平均值.(要求用指向数组的指

inta[30];//存入就不需要写了吧?intb[30];intatb=0;for(inti=0;i

#include#defineCOUNT100main(){inta[COUNT],i,x,no=0;for(i=0;i

同时与n互质的数------这个不太明白?能说一下吗?下面1000以内质数算法.PrivateSubCommand1_Click()Text1.Text=""Fori=1To1000k=1Forj=2

#include#include#includeintmain(){inta[15],i,j;srand(time(NULL));for(i=0;i<15;i++)a[i]=rand()%100;fo

#includeintmain(){float*p,*q,*max,*min,ave=0;intn;scanf("%d",&n);q=(float*)calloc(n,sizeof(float));f

这道题我也错过好几次...先找最大值,然后更改,再找最小值,再改就可以了...数据范围不大,可以的再问：是的

#include#includemain(){\x09inta[50],n,i,j,t;\x09printf("inputn:");\x09scanf("%d",&n);\x09printf("inp

publicstaticvoidmain(String[]args){intarray[]=newint[20];intresult=0;Listlist=newArrayList();System.

#includevoidmain(){inta[100];inti,min;printf("输入100个数\n");for(i=0;i

publicclassTest{publicstaticintfib(intn){if(n==1||n==2)return1;elsereturnfib(n-1)+fib(n-2);}publicst

#includeintsearch(intlist[],intn,intx){\x09inti;\x09for(i=0;i

voidmain(){floata[10];float*p=a,max,min,pj=0;inti=0,j;for(;i

inta[20];a[0]=1;a[1]=1;for(inti=2;ia[i]=a[i-1]+a[i-2];for(inti=0;i{for(intj=0;j

#includevoidinput(inta[],intn)//输入{inti;printf("请输入%d个数,用空格隔开\n",n);for(i=0;i

PrivateSubCommand1_Click()Dima()AsIntegern=Val(InputBox("N="))ReDima(n)Print"Before:&

#include#include#defineN20voidmain(){inti,k,j,a[N];k=0;printf("Pleaseinputtwentynozeronumbers\n");fo

inti,geshu=0,sum=0,a[100],aver;scanf("%d",&a[i]);for(i=0;i

#includeintmain(){doubled[10],sum=0,ave=0;inti;for(i=0;i

#include#defineN10intmain(){inti;inta[N],b[N],*p,*q;floatx;for(p=a;p

#includevoidmain(){intn,min,a[100],i,t,e;while(scanf("%d",&n)!=EOF&&n