输入两个整数,求出它们的商数

#includevoidmain(){inta,b;printf("Inputtwointegers:");scanf("%d%d",&a,&b);printf("和:a+b=%d\n",a+b);p

C/C++版本,请楼主参考.#include"stdio.h"#include"stdlib.h"intgetMax(inta,intb){if(a>b)returna;elsereturnb;}vo

#includemain(){inta,b,c,d,max,min;scanf("%d,%d,%d,%d",&a,&b,&c,&d);max=a;min=a;if(b>max)max=b;if(c>m

1.main(){inta,b;scanf("%d%d",&a,&b);printf("%d%d",((int)a/b),a%b);}2.main(){inta,b;scanf("%d",&a);b=

#includevoidmain(){inta[10],i,sum=0,count=0;printf("请输入10个整数：\n");for(i=0;i再问：奇数输出不了 再答：不好意思，我是

#includeintmain(){\x09inta,b;\x09scanf("%d%d",&a,&b);\x09printf("商为%.2f余数为%d\n",1.0*a/b,a%b);\x09ret

是输入结束不会还是取整数小数不会?再问：都不会，完全没有思路，只有寻求帮助了再答：������֪��˼·����ֱ��Ҫ����再问：ֱ��Ҫ����ϣ������C++��д��˳��˵������

算法一：#includemain(){intn1,n2,gcd=1,k=2;scanf("%d%d",&n1,&n2);while(k0;i--)if(n1%i==0&&n2%i==0)printf(

#includevoidmain(){intx,y,p;scanf("%d%d",&x,&y);if(x

#include#incluedvoidmain(){inta;intb;intc,d;a=1500,b=350;c=a/b;//商数d=a%b;//余数pritf("商数为:%d\n",c);pri

#includeintmain(){inta,b,c,d=0;scanf("%d%d",&a,&b);c=a/b;d=a%b;printf("商是:%d\n",c);printf("余数是:%d\n"

#include"stdio.h"main(){inta=0,b=0,c=0,d=0;printf("请输入两个整数：");scanf("%d,%d",&a,&b);if(b==0)printf("输

http://zhidao.baidu.com/link?url=wyic3NEB45i2K9YZE2SpNiAV4aD7rZHpluBlyF76zg0n_8wr1t6-KOYm6eYY23KqG5n

设除数为x被除数为x*12+26所以x+(x*12+26)+12+26=45413x=390x=30

#include#defineSURPLUS(a,b)(a%b)main(){inta,b;printf("pleaseinputinteger:");scanf("%d,%d",&a,&b);pri

#include"stdio.h"intmain(){inta,b;scanf("%d%d",&a,&b);if(b==0)b=1;printf("和%d\n",a+b);printf("积

需要“大数相乘”的算法,以前上算法课的时候老师讲过,有个公式的.你可以搜一下,用分治解决的.http://bbs.cfan.com.cn/thread-368381-1-1.html

#includevoidmain(){inta,b,c,min,max,cha;scanf("%d%d%d",&a,&b,&c);min=a;max=a;if(b>max){max=b;}if(bma

//#include"stdafx.h"//vc++6.0加上这一行.#include"stdio.h"voidmain(void){intm,n,k,l;while(1){printf("Typem

#include"stdio.h"voidmain(){intm,n,r,tm,tn;scanf("%d%d",&n,&m);if(m