输入整数a和b,若a2 b2小于80,则输出a2 b2结果,否则输出a b之和.-搜答案-智慧作业帮

pravitesubcommand1_Click()dimn%n=inputbox("请输入一个整数","输入整数")ifnmod3=0andnmod7=0thenprint"A"elseprint"

∵√25＜√28＜√36∴5＜√28＜6又∵a和b为两个连续的整数∴a=5,b=6∴a+b=5+6=11

#include　　voidmain(){inti;intj[6];inta;intsum=0;for(i=0;i

inta,b;scanf("%d%d",&a,&b);if(a>100||b>100){if(a>100)printf("%d\n",a);if(b>100)printf("%d\n",b);}els

#includevoidmain(){floata,b,sum,change;scanf("%f,%f",&a,&b);sum=a*a+b*b;if(sum>100){change=sum/100;w

交换的话,其实有三种方法：下面列举出来,你可以选取一种.第一种：也就是中间值的交换：这里我就直接盗用下一楼的答案拉：publicstaticvoidmain(String[]args){inta=2;

if(aif(a>100)printf("a=%d\n",a/100);if(b>100)printf("b=%d\n",b/100);

a=Int(InputBox("a="))b=Int(InputBox("b="))c=Round(Rnd()*(a-b)+b,0)MsgBox"a="&a&";b="&b&";c="&c

voidfun(int*a,int*b){intc=0;c=*a;*a=*b;*b=c;return;}

用C语言#include<studio.h>main(){inta,b,cprintf("PleaseEnteraandb:");scanf("%d,%d",&a,&b);c=a%b;if

#includeintmain(){inta,b;printf("inputtwonumber:");scanf("%d%d",&a,&b);if((a*a+b*b)>=100)printf("\n%

#includeusingnamespacestd;intmain(){inta,b;cin>>a>>b;if(a%b==0&&a>b){cout

//楼主,这里的大于100,指的是它们的和大于100,还是各个数字呀?//下面的例子,理解为各个数字大于100,如果理解有误,楼主可以做简的修改#includevoidmain(){inta,b,c,

9x-a>=0,解之得x>=a/98x-

#includeintmain(){inta,b;printf("inputtwonumber:");scanf("%d%d",&a,&b);if((a*a+b*b)>=100)printf("\n%

#include"stdlib.h"#include"stdio.h"voidmain(){inta,b;scanf("%d%d",&a,&b);a=a*a;b=b*b;inttemp=a+b;if(

(a²＋b²－c²)²－4a²b²=[(a²＋2ab＋b²)－c²]×[(a²－2ab＋b²

*a/108所以8

a>0,b>0;ab/10

a/b等到的是商,a%b求得的是余数.由于是整数,所以a/b得到的是整数,余数部分被省略,需要另求!