输出一个华氏温度,要求输出摄氏温度.公式为c=5 9(F-32) c语言程序
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intmain(){floatc,f;printf("pleaseinputthef=");scanf("%f",&f);c=5/9*(f-32);printf("thec=%f",c);}再问:你运
#includevoidmain(){floatc,f;scanf("%f",&f);c=5.0/9*(e-32);printf("%f",c);}
代码#includevoidmain(){doublea,c;scanf("%lf",&a);c=9.0/5*(a-32);printf("%.2lf\n",c);}
我有一本答案是谭浩强的,如果你是用这个的话hi我,这道题目很简单,不看答案都没有问题.我记得里面有这道题目
#includemain(){floattemperature;scanf("%f",&temperature);temperature=5.0/9*temperature+32;printf("%f
#includevoidmain(){floatc,f;printf(“请输入一个华氏温度:”)scanf(“%f”,&f);c=(f-32)/9;printf(“摄氏温度为:%5.2f\n”);}编
你是要求用C语言吗?再问:是再答:这个我可以编,但是你地公式写得不清楚。c代表什么,F代表什么。要是一个代表摄氏,一个代表华氏,那肯定是有等号的。你再好好看看。把公式发过来。再问:C代表摄氏温度,F代
#includevoidmain(){floatF;floatC;scanf("%f",&F);printf("%f",C=5/9*(F-32);}采纳吧少年,这题我们刚做过
5.0不能换成5,否则5/9=0可用float,相应改为floatc;scanf("%f",&c);
华氏转摄氏公式:T℉=1.8t℃+32#includeintmain(){floatf,c;printf("输入华氏温度:\n");scanf("%f",&f);c=(f-32)/1.8;printf
LZ的大括号好像有点问题.还有那个输出也打错了.不过这样填是正确的:①:fahr②:clesius=5*(fahr-32)/9;③:fahr+=step;这是完整代码:#includemain(){i
#includemain(){floatf,c;printf("pleaseenterF:");scanf("%f",&f);c=5.0*(f-32.0)/9.0printf("%f",c);}
#include<stdio.h>int main(){ float F,c; &nbs
#includeintmain(){floatF,c;while(1){printf("请输入华氏温度:");scanf("%f",&F);c=5*(F-32)/9;printf("摄氏温度为:%0.
#include#includeintmain(void){floatc,f;printf("请输入华氏度:\n");scanf("%f",&f);c=(f-32)/9*5;printf("%.2f℉
#includefloatfun(floatC){floatF;F=C*9/5+32;returnF;}voidmain(){floatC,F;printf("输入摄氏温度:");scanf("%f"
用C写吗?#includeintmain(){floatF;printf("请输入华氏温度:");scanf("%f",&F);printf("与华氏%0.3f°相应的摄氏温度为:%0.3f°\n",
#includeintmain(){floatc,f;printf("请输入华氏温度:");scanf(("%f",&f);c=5*(f-32)/9;printf("摄氏温度为:%.2f\n",c);
华氏度(℉)=32+摄氏度(℃)×1.8,摄氏度(℃)=(华氏度(℉)-32)÷1.8.