作业帮vb编写2*3矩阵的行和列转换
来源：学生作业帮助网 编辑：作业帮 时间：2024/08/24 10:25:58
PrivateSubCommand1_Click()DimsumAsDoubleDimiAsLongDimnAsDoublen=((1/(10^-5))+1)/2'正好等于10^-5时候n的值
#includevoidmain(){inti,j,row=0,colum=0,max;inta[3][4]={{1,2,3,4},{9,8,7,6},{-10,10,-5,2}};max=a[0][
StatusMultSMatrix(TSMatrixM,TSMatrixN,TSMatrix*Q){/*求稀疏矩阵的乘积Q=M×N*/inti,j;ElemType*Nc,*Tc;TSMatrixT;
Dim i As Integer, j As Integer, a(1 To 3, 1 T
ModuleModule1SubMain()DimA(,)AsInteger={{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5,6,7,8,9,0},{1,2,3,4,5,6,7,8
行向量:123和456和789列向量:147和258和369
我最近在看C++C语言不一定用的很专业见谅啊!#includevoidmain(){intarray[3][4]={0};inti,j,sun=0;printf("Pleaseinputaarray:
#include<stdio.h>int main(){ int a[2][3]; &n
假设矩阵为一个数组a(1tom,1ton)SubMax()Dimb()AsSingle,maxxAsSingleFori=1Tomb(i)=a(i,1)Forj=1TonIfb(i)
#includevoidmain(){\x09inta[3][2]={1,2,3,4,5,6};\x09intb[2][3],i,j;\x09for(i=0;i
初始化二维2×3矩阵：DimMyArray(1,2)AsInteger然后运行过程中加入代码定义二维3×2矩阵：ReDimPreserveMyArray(2,1)AsInteger再用一个镶嵌For.
mc[i][j]=ma[i][0]mb[0][j]+ma[i][1]mb[1][j]+ma[i][2]mb[2][j]公式是不是应该这样啊
#includeintmain(){inti,j,m,n,p,x;inta[2][3],b[3][2],c[2][2];for(i=0;i
#include#defineN2#defineM3voidmain(void){inti,j;inta[N][M];intb[M][N];for(i=0;i
intfun(intarray[3][3]){inti,j,t;for(i=0;i
#defineM3#defineN3intmain(){inti,j,sum=0,Min,posi=0,posj=0,arry[M][N];for(i=0;i
Private Sub Command1_Click()Dim a(4, 2) As Integer, b(2, 4)&
PrivateSubCommand1_Click()RandomizeTimerDimnAsInteger,mAsIntegerDimarr1()AsInteger,arr2()AsIntegerDi
main(){inta[3][3]={{1,2,3},{4,5,6},{7,8,9}}inti,j;intsum=0,s=0;for(i=0;i