VB计算下面级数前N次的部分和,并输出该级数最后两次的绝对值-搜答案-智慧作业帮

#includeintmain(){intn,i,sum;scanf("%d",&n);sum=0;for(i=1;i

PrivateSubCommand1_Click()DimnAsInteger,阶乘项AsLong,阶乘和AsLongDon=Val(InputBox("请输入阶乘的项数（N≤8）"))LoopUnt

PrivateSubCommand1_Click()Dimn%,i%,y%,a%a=0y=1n=Val(text1.Text)Fori=1Tona=a+1y=y*aNextiEndSu

/>Private Sub Form_Click()'1、* 编写程序,计算并输出下面数列中前n项的和.(设n=20)'

inta=1;intb=2;intsum=0;for(intn=1;n再问：正确么再答：完整正确的代码如下：#include#include#includevoidmain(){inta=1;intb

Un=S(n+1)-Sn=1/(2n+2)+1/(2n+1)-1/(n+1)=1/(2n+1)-1/(2n+2)Un的部分和=1/3-1/(2n+2)收敛于1/3再问：un不是应该等于sn-s(n-1

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doubley=k=s=t=1;这个分开来写：doubley=1,k=1,s=1,t=1;

#includeintmain(){inti,sum=0;for(i=1;i

main(){inta,sum,i;for(i>0;i

解题思路：根据题意计算..................................解题过程：附件

PrivateSubCommand1_Click()DimSAsDouble,jcAsDouble,NAsIntegerjc=1N=Val(InputBox("请输入N"))Fori=1ToNjc=j

#include"stdio.h"main(){intn,s;n=1;s=0;while(n

PrivateSubCommand1_Click()DimiAsLong,sumAsLongFori=1To50Step2sum=sum+i*(i+1)*(i+2)NextMsgBox"级数前50项奇

Rem语言：VisualBasic6.0SubMain() '开始 S=0 For i=1To 50 &nb

#includevoidmain(){inta1,a2;longintresult=0;inti;for(i=1;i

longn=0;for(inti=1;i

1.dimi,jasIntegerfori=1to20j=j+i*(i+1)*(i+2)nextimsgboxj

#include"stdio.h"voidmain(){floatans=0;inti;for(i=1;i

u1=S1=1当n≥2时,Un=Sn-Sn-1=2n/(n+1)-2(n-1)/n=2/(n²+n)

VB计算下面级数前N次 的部分和,并输出该级数最后两次的绝对值