vb随机产生n个10-100的整数,用过程求最大值最小值总和平均值

窗体中加命令按钮,单击事件代码如下：PrivateSubCommand1_Click()  Randomize  Dima(1To20)AsInteger&nb

Private Sub Command1_Click()Text1.Text = ""Dim A(1 To 1

PrivateSubForm_Load()Dima(10),i,x,jAsIntegerDimyAsStringFori=0To9Randomizea(i)=Int(Rnd(1)*101)x=x+a(

PrivateSubCommand1_Click()RandomizeDima(10)AsInteger,imasasinteger,iminasinteger,Averageasintegerima

command1完成第一题,command2完成第二题PrivateSubCommand1_Click()Dimx%(1To10),n%,i%n=1DoWhilen

帮你写好了,这个是工程文件,下载下来就可以了.以下是源码:PrivateSubCommand1_Click()DimA(10)AsDouble,LAsInteger,BAsDouble,CAsDoub

这样才对初始化应加在For循环里s要变为双精度（这样平均数才有小数点后几位）楼主试我这个：PrivateSubCommand1_Click()Dimi%,j%,max%,min%,s%Fori=1To

Dima(10)Fori=0To9a(i)=Int(100+100*Rnd)NextiFori=0To8Forj=iTo9Ifa(i)t=a(i)a(i)=a(j)a(j)=tEndIfNextjNe

我已经上机验证过了,正确.思路：产生80个随机数,把这80个随机数由小到大排序,然后从第1个到第80个的顺序挑选偶数,赋值给字符串s1,够10个换行.再从第80个到第1个的顺序挑选奇数,赋值给字符串s

Dimy%,x%Fori=1To10x=Int(Rnd*100)'[0,99]Printx;Ifi=1Theny=xElseIfy>xTheny=xEndIfNextiPrint"最小值";x如果是N

dimsasinteger,aasinteger,basinteger,casintegers=Rnd()*900+100a=s\100b=s\100-a*10c=smod100-b*10然后用if判

subform_click()dima%(20)fori=1to20a(i)=int(rnd()*10+1)printa(i),nextendsu

通过SubMain启动Submain()Dima(9)AsInteger,pAsDouble,iAsInteger,nAsIntegerp=0n=0Fori=0To9a(i)=Rnd*100p=p+a

'试一下：PrivateSubCommand1_Click()Dima(1To10)AsStringDimiAsInteger,jAsIntegerFori=1To10Randomizea(i)=Ch

functionsj(i%,a%,b%)aslongDimx%x=Int(Rnd*(b-a+1))+asj=xEndfunctionPrivateSubCommand1_Click()Dimn%,a%

DimMyValue(10)AsIntegerDimi,j,pAsIntegerFori=0To9RandomizeMyValue(i)=Int((100*Rnd)+1)NextFori=0To9Fo

PrivateSubCommand1_Click()DimZs(1To35)AsIntegerFori=1To35RandomizeZs(i)=Int(61*Rnd)+20PrintZs(i);Nex

是“奇数”吗..?另外一共就产生十个,每行显示十个……是不是产生任意多个,然后每行输出十个?奇数的话范围就在11~99之间,用2n+1法产生奇数的话n的取值范围就是5~49新建工程,窗体上放个文本框,

vb6测试通过PrivateSubCommand1_Click()Dima(10)AsInteger,tempAsInteger,iAsInteger,jAsIntegerRandomizetemp=

Option ExplicitPrivate Sub Form_Load()RandomizeMe.AutoRedraw = TrueDim