x y分之x x y分之2y

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分式通分:xy分之2,xy-x的平方分之3y

2/xy=2(y-x)/xy(y-x)3y/(xy-x^2)=3y^2/xy(y-x)如果不懂,请追问,祝学习愉快!

(X+Y分之X+X+Y分之2Y)乘X+2Y分之XY除以(X分之1+Y分之1)要有过程

原式=[(x+2y)/(x+y)][xy/(x+2y)]÷[(x+y)/xy]=[xy/(x+y)]×xy/(x+y)=x²y²/(x+y)²

计算:2x+2y分之3y + x²+xy分之2xy

2x+2y分之3y+x²+xy分之2xy=3y/2(x+y)+2xy/x(x+y)=3y/2(x+y)+2y/(x+y)=7y/2(x+y)如追加其它问题,再问:这道题要通分,能不能化成同分

计算(3y分之2x)×(4y分之3x)÷(4分之1xy)

=(2X/3Y)*(3X/4Y)*(4/xy)=(2x*3x*4)/(3y*4y*xy)=2x/(y^3)

XY-2Y二次方分之X二次方-2XY=Y分之 利用分之的基本性质

XY-2Y二次方分之X二次方-2XY=Y(X-2Y)分之X(X-2Y)约分=Y分之X

y分之x等于2分之1 xy怎么算

绝对算不出来再答:如果是一道题发图咯再问:x平方减xy加y平方分之x平方加2xy加y平方他给你条件是y分之x等于2分之1xy再问:吧xy无视掉再答:马上再答:化成Y等于2X在带入再问:然后怎么样再答:

x+y分之xy=5,y+z分之yz=2分之7,z+x分之zx=4,则xy+yz+zx分之xyz=?

xy/(x+y)=51/x+1/y=1/5yz/(y+z)=7/21/y+1/z=2/7zx/(z+x)=41/x+1/z=1/4(xy+yz+zx)分之xyz=1/(1/x+1/y+1/z)=280

已知x分之1+y分之1=-2,则x+xy+y分之x-xy+y的值等于

1/x+1/y=-2则(x-xy+y)/(x+xy+y)分子分母同除以xy=(1/x+1/y-1)/(1/x+1/y+1)=(-2-1)/(-2+1)=3

已知x+y分之xy=2,那么3x-5xy+3y分之3xy-x-y=

xy/(x+y)=2∴xy=2(x+y)(3xy-x-y)/(3x-5xy+3y)=[6(x+y)-x-y]/[3x+3y-10(x+y)]=5(x+y)/[-7(x+y)]=-5/7

已知X+Y分之XY=2,求-X+3XY-Y分之3X+5XY+3Y

因为X+Y分之XY=2,所以XY=2(X+Y)代入后面的分子式得:13(X+Y)/5(X+Y)=13/5

2x+2y分之3y+x^2+xy分之2xy

原式=3y/2(x+y)+2xy/x(x+y)=(3xy+4xy)/2x(x+y)=7xy/2x(x+y)=7y/(2x+2y)再问:不对再答:哦,不信就算了

(-3分之1xy)的平方×[xy(2x-y)-2x(xy-y的平方)]

原式(-xy/3)²*[xy(2x-y)-2x(xy-y²)]=(x²y²/9)(2x²y-xy²-2x²y+2xy²)

2x+2y分之3y 加 x²+xy分之2xy

3y/(2x+2y)+2xy/(x²+xy)=3y/(2x+2y)+2y/(x+y)=3y/(2x+2y)+4xy/(2x+2y)=7y/(2x+2y)

(x+y分之x加x+y分之2y)乘x+2y分之xy除(x分之1加y分之1)等于?

原式=[(x+2y)/(x+y)]×[xy/(x+2y)]÷[(x+y)/xy]=[(x+2y)/(x+y)]×[xy/(x+2y)]×[xy/(x+y)]=x²y²(x+2y)/

已知x分之1减y分之1等于4,求x+7xy-y分之x-2xy-y

由已知条件可得:x-y=-4xy,(也就是在等式两边乘xy后整理,即可),代入所求的式子里分母为-4xy+7xy,即3xy;分子为-4xy-2xy,即-6xy,化简得-2

若x+y分之xy=2,则-x+3xy-y分之3x-xy+3y=多少?

xy/(x+y)=2(x+y)/xy=1/21/x+1/y=1/2(3x-xy+3y)/(-x+3xy-y)=(3/y-1+3/x)/(-1/y+3-1/x)=[3(1/x+1/y)-1]/[(3-(

已知X+Y分之XY等于3,求-X+3XY-Y分之2X-3XY+2Y

设x+y=axy=b,则b/a=3b=3a所以-X+3XY-Y分之2X-3XY+2Y可以写成(2a-3b)/(3b-a)=-7/8

已知xy分之【x加y】等于2分之一,则【xy加x加y】分之xy等于多少

xy分之【x加y】等于2分之一xy=2(x+y)【xy加x加y】分之xy=2(x+y)/[2(x+y)+x+y]=2(x+y)/[3(x+y)]=2/3

(xy-x²)除以xy分之x²-2xy+y²乘以x²分之x-y

(xy-x²)÷xy分之x²-2xy+y²乘x²分之x-y=-x(x-y)×xy/(x-y)²×(x-y)/x²=-y∴结果与x的值没有关系

(x+y分之x + x+y分之2y)乘x+2y分之xy 除以(x分之1+y分之1)同样用两...

是这样的形式吗?[x/(x+y)+2y/(x+y)]×[xy/(x+y)]÷(1/x+1/y)一:原式=(x+2y)/(x+y)×[xy/(x+2y)]÷[(x+y)/xy]=x²y&sup