x2次方y-2xy2次方 y3次方
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a^3+b^3=(a+b)(a^2-ab+b^2)a^3-b^3=(a-b)(a^2+ab+b^2)(x+y+z)^3-x^3-y^3-z^3=(y+z)[(x+y+z)^2+(x+y+z)x+x^2
原式分解因式得x^3y^3(2x-y)=(xy)^3(2x-y)=8/3.(x^3表示x的3次方)
1、x+y=a,xy=b①x²+y²=x²+2xy+y²-2xy=(x+y)²-2xy=a²-2b②x³+y³=(x
=(x+2y)(x-2y)(x-2y)
∵x+y+z=0,∴z=(-x-y)x^3+y^3+z^3=x^3+y^3-(x+y)^3=x^3+y^3-x^3-y^3-3x^2y-3xy^2=-3xy(x+y)=3xyz
1)18m(m-n)的平方-12(n-m)的平方=6(m-n)²2)x的m+3次方y-x的m+2次方y平方+x的m+1次方y3次=x的m+1次方y(x²-xy+y²)再问
已知x=2-√3,y=2+√3,求代数式x2次方+y2次方值xy=4-3=1x+y=4x²+y²=(x+y)²-2xy=16-2=14再问:谢谢你,但我要那种初级复杂的过
(-2分之1的x的2次方y)的三次+(0.5x)的2次方乘y的三次(x2次)2次=-1/8x的6次方y的3次方+1/4x的6次方y的3次方=1/8x的6次方y的3次方如果本题有什么不明白可以追问,如果
(2m+1)x^2y^(n+1)是关于x,y的系数为1的5次单项式2m+1=12+(n+1)=5m=0n=2
原式=x3+3x2y-5xy2+6x3+1-2x3+y3+2xy2+x2y+2-4x2y-7x3-y3+4xy2+1=-2x3+xy2+4,由于y为偶次幂,故误把“x=3,y=-1”写成“x=3,y=
^3代表3次方,^2代表平方X^3+X^2-Y^3-Y^2=(x^3-y^3)+(x^2-y^2)=(x-y)(x^2+xy+y^2)+(x-y)(x+y)=(x-y)(x^2+xy+y^2+x+y)
xy³+xy²+xy=xy(y²+y+1)
y(x+2)/(x-2)(x+2)=y/(x-2)提取yx²-4=(x-2)(x+2)
A-B=(x3+2y3-xy2)-(﹣y3+x3+2xy2)=x³+2y³-xy²+y³-x³-2xy²=3y³-3xy²
题目是否有误?原式左边化简后等于:=(x-y)^3,再表达成=x^3+(),意义不大吧x^3-3x^2y+3xy^2-y^3=x^3+(3xy^2-3x^2y-y^3)
1.求证:(x+y)(x²+y²)(x³+y³)≥8x³y³.分情况,使用基本不等式证明.①x、y都是正数时,∵X+Y≥2√(XY)①x&s
3x³y-3x²+xy²-2y³
X^2+y^2=(x+y)^2-2Xy=a^2-2bx3次方+y3次方=(x+y)(X^2+y^2-xy)=a(a^2-2b-b)=a^3-3abx4次方+y4次方=(x^2+y^2)^2-2x^2y
x²-x=7y²-y=7相减x²-x-y²+y=0(x+y)(x-y)=x-yx-y≠0约分x+y=1x²-x=7y²-y=7相加x&sup