x=3t^2 (1 t^2),y=-t^2 (1 t^2)
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x=(√3/2)(2t);y=2-(2t)/2,令2t=T,则X=√3T/2,y=2-T/2,则|T|表示直线上任一点到(0,2)的距离,将X=√3T/2,y=2-T/2代入y^2=2x得:(2-T/
x=y^2-y-2再问:求解答过程再答:y=t-1,t=y+1,代入,x=(y+1)^2-3(y+1)+1=y^2+2y+1-3y-3+1=y^2-y-1检验的时候发现上面回答的错了,答案是y^2-y
x-1=(t+1)/(t-1)-1=2/(t-1)t-1=2/(x-1)t=(x+1)/(x-1)t^2+t+1=(x+1)^2/(x-1)^2+(x+1)/(x-1)+1=(3x^2+1)/(x-1
3X+5Y-11=0由X=-3+(5/T+1)Y=4-(3/T+1)两式得
由x=1-t/2+t得t=2(x-1)将其代入y=5+4t/3-2t得y=5-4(x-1)/3
x=2t/(1+t)x+xt=2tt=x/(2-x)代入y,得:y=x/(2-x)/[1-x/(2-x)]=x/[2-x-x]=x/(2-2x)再问:看不懂,请详细介绍再答:从第一个方程先解出t,它是
答案:y=2x+3x=2t,y=4t+3因为2x=4t4t+3=y
t=+1,t=-1斜率都是无限,怀疑你的图像画错了
y=ln(1+t)t=e^y-1x=e^(2y)-e^y两边同时对x求导得dy/dx=1/(2e^(2y)-e^y)=1/(2(1+t)^2-1+t)=1/(2t^2+3t+1)
明显你是对的.答案是哪里来的,明显不对.
x=(1-t)/(1+t)1-t=x(1+t);t=(1-x)/(x+1);将t代入y代数式,化简后得出y=(5x+1)/(5x-1)
参数方程求导:d^2y/dx^2=d[dy/dx]/dx=d[(dy/dt)/(dx/dt)]/dx=d[y'/x']/dt*dt/dx=(y''x'-y'x'')/x'^2*1/x'=(y''x'-
x/y=1/t,t=y/x代入得:x=3y/x/(1+y^2/x^2)x^2=3yx^2/(x^2+y^2)x^2+y^2=3y此为一个圆.
x=3t^2/(1+t^2)x(1+t^2)=3t^2x+xt^2-3t^2=0x+t^2(x-3)=0t^2(x-3)=-xt^2=-x/(x-3)y=(5-t^2)/(1+t^2)y(1+t^2)
x²+y²=4(1+t²)/(1+t²)²=4/(1+t²)=2x整理得到:(x-1)²+y²=1如果用圆的参数方程表示
x=3t+1t=(x-1)/3y=2t-1=(2x-5)/3
y=∫(t-1)^3(t-2)dt,dy/dx=(x-1)^3(x-2).
[x-(t+3)]²+[y+(1-4t²)]²=-16t^4-9+(t+3)²+(1-4t²)²是圆则r²=-16t^4-9+(t