x=t^2-3t 1 y=t-1
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f(x)=x^2-2x+3=(x-1)^2+2,g(t)要分段表达:(1).t1时,f(x)在[t,t+1]单调上升,g(t)=f(t)=t^2-2t+3.再问:单调是什么……不好意思我很笨……再答:
x=y^2-y-2再问:求解答过程再答:y=t-1,t=y+1,代入,x=(y+1)^2-3(y+1)+1=y^2+2y+1-3y-3+1=y^2-y-1检验的时候发现上面回答的错了,答案是y^2-y
x-1=(t+1)/(t-1)-1=2/(t-1)t-1=2/(x-1)t=(x+1)/(x-1)t^2+t+1=(x+1)^2/(x-1)^2+(x+1)/(x-1)+1=(3x^2+1)/(x-1
3X+5Y-11=0由X=-3+(5/T+1)Y=4-(3/T+1)两式得
3t^2-7t+2=0(3t-1)(t-2)=0t1=1/3,t2=24x^2-1=8x4x^2-8x-1=04x^2-8x+4=54(x-1)^2=5x-1=√5/2或x-1=-√5/2x=1+√5
x=2t/(1+t)x+xt=2tt=x/(2-x)代入y,得:y=x/(2-x)/[1-x/(2-x)]=x/[2-x-x]=x/(2-2x)再问:看不懂,请详细介绍再答:从第一个方程先解出t,它是
f(x)=x^2+4x+3对称轴是x=-2函数g(t)表示函数f(x)在区间[t,t+1]的最小值下面分类讨论:(1)若t+1<-2,即t<-3则g(t)=f(t+1)=(t+1)^2+4(t+1)+
t=+1,t=-1斜率都是无限,怀疑你的图像画错了
t²-2t-3=-3t+3t²2t²-t+3=0a=2,b=-1,c=3所以△=b²-4ac=-23
函数表达式看不懂;是不是:f(x)=(x-2)+|x|+3再问:是的再答:
x=(1-t)/(1+t)1-t=x(1+t);t=(1-x)/(x+1);将t代入y代数式,化简后得出y=(5x+1)/(5x-1)
x/y=1/t,t=y/x代入得:x=3y/x/(1+y^2/x^2)x^2=3yx^2/(x^2+y^2)x^2+y^2=3y此为一个圆.
将函数求导得:f'(x)=2tx+2t^2最小值时,f'(x)=0,所以解得x=-t,将x=-t代入函数,可求出值
x=2+2t-3t-3t的平方合并得到x=2-t-3t的平方
x=3t^2/(1+t^2)x(1+t^2)=3t^2x+xt^2-3t^2=0x+t^2(x-3)=0t^2(x-3)=-xt^2=-x/(x-3)y=(5-t^2)/(1+t^2)y(1+t^2)
高三数学题函数f(x)=(1-t)ln(x-1)+x*x/2+(1-t)x+t*t/2+t,且t>11)求f(x)的单调区间解析:∵函数f(x)=(1-t)ln(x-1)+x*x/2+(1-t)x+t
y=∫(t-1)^3(t-2)dt,dy/dx=(x-1)^3(x-2).
∵f(x)=x^2-2x-3=(x-1)^2-4∴对称轴x=1分类讨论1.x=1∈[t,t+1]时,即0≤t≤1时,g(t)=-4;2.x=1t+1即t=2时,g(t)的最小值是g(2)=-3g(t)