x^2 y^2-z=0

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三元一次方程组x=y-z,x+y-z=2,x-2y+z=0

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已知x、y、z满足方程组:x+y-z=6;y+z-x=2;z+x-y=0 求x、y、z的值

x+y-z=6y+z-x=2z+x-y=0三式相加得x+y+z=8-得2z=2z=1-得2x=6x=3-得2y=8y=4x=3y=4z=1

试证明(x+y-2z)+(y+z-2x)+(z+x-2y)=3(x+y-2z)(y+z-2x)(z+x-2y)

有这样的公式:a^3+b^3+c^2-3abc=(a+b+c)(a^2+b^2+c^2-ab-bc-ca)左边减右边,证明:(x+y-2z)^3+(y+z-2x)^3+(z+x-2y)^3-3(x+y

{2x-2y+z=0,2x+y-z+1,x+3y-2z=1

①2x-2y+z=0②2x+y-z=1③x+3y-2z=1你可以2式-3式,得出4式x-2y+z=01式=4式,得出x=o,代入1式,得出2y=z继续代入2式或者3式,得出Y=-1,Z=-2

2x+5y+4z=0,3x+y-7z=0,则x+y-z=?

解法2:2x+5y+4z=0式①3x+y-7z=0式②x+y-z=?式①×3-式②×23(2x+5y+4z)-2(3x+y-7z)=015y+12z-2y+14z=013y+26z=0式③式①-式②×

2x-2y+z=0 2x+y-z=1 x+3y-2z=1

①+②4x-y=12②-③3x-y=1有上得x=0y=-1代入②得z=-2

如果|x+y+z-6|+|2x+3y-z-12|+|2x-y-z|=0求x,y,

x+y+z-6=02x+3y-z-12=02x-y-z=0组成方程组再解x=2y=3z=1

1.已知x,y,z满足2│x-y│+(根号2y-z)+z平方-z+(1/4)=0,求x,y,z值.

1.z²-z+1/4=(z-1/2)².绝对值、根号、平方数都是非负的,而相加为0.所以都为0.即x=y,2y=z,z=1/2.所以x=y=1/4,z=1/2.2.2002x200

x-3y+z=0,3x-2y-4z=0,则x:y:z=多少?

由x-3y+z=0可变形为z=3y-x代入到3x-2y-4z=0简化出x=2y,再将这个关系带入到z=3y-x中,可得出z=y,所以x:y:z=2:1:1

x+2y-4z=0 3x+y-z=0,则x:y:z=

x+2y-4z=0.[1]3x+y-z=0.[2][1]*3:3x+6y=12z.[3][3]-[2]:5y=11zy=11/5zx=4z-2*11/5z=-2/5zx:y:z=(-2/5z):(11

已知(x+y+z)^2=x^2+y^2+z^2,证明x(y+z)+y(z+x)+z(x+y)=0

将(x+y+z)²展开有(x+y+z)²=x²+y²+z²+2xy+2xz+2yz=x²+y²+z²所以2xy+2xz+

X+Y+Z=0,X-Y-Z=0,Y=2,求x和z

0和-2再答:0和-2再问:说清是X等于几和z等干几

解下列方程组x+y+z=18 x+y-z=0 x-2y+z=0

(1)+(2)得2x+2y=18x+y=9(4)(2)+(3)得2x-y=0(5)(4)+(5)得3x=9∴x=3把x=3代入(4)得3+y=9∴y=6把x=3,y=6代入(1)得3+6+z=18∴x

3x+2y+z=9,x+y+2z=0,2x+3y-z=11

z=2x+3y-11然后代入式得到5x+5y=20可得到x+y=4得到z=-2,然后代入1和3式然后1式乘以2,3式乘以2,可得到y=1,然后代入任意一式得到x值.再问:过程再答:你敢不敢给我给分啊?

x+y-z=0 2x-3y+2z=5 x+2y-z=3

x+y-z=0①,2x-3y+2z=5②,x+2y-z=3③,①-③=x+y-z-﹙x+2y-z﹚=﹣3,y=3,将y=3代入①②中分别为,x-z=﹣3④,x+z=7⑤,④﹢⑤=2x=4,x=2,将x

已知x,y,z满足方程组{x+y-z=6,y+z-x=2,z+x-y=0,求x,

X+Y-Z=6.aY+Z-X=2.bZ+X-Y=0.ca,b,c三式相加X+Y+Z=8.dd式-a式2Z=2Z=1d式-b式2X=6X=3d式-C式2Y=8Y=4

已知 3x-y+2z=0 2x+y-3z=0,求x :y :z.

两式相加,得3x-z=0可得z/x=5将z=5x代入1式13x-y=0得y/x=13所以x:y:z=1:13:5

x+y+z=4 x-2y+z=-2 x+2y+3z=0求解

x+y+z=4(1)x-2y+z=-2(2)x+2y+3z=0(3)(1)-(2)3y=6y=2代入(1),(3)x+z=2(4)x+3z=-6(5)(4)-(5)-2z=8z=-4x=2-z=6所以