x分之一减3x分之2加(3x减2)分之x
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x+5/2=-[(2-3x)/8-(4x+3)/4)]8x+20=3x-2+8x+6x=16/3
x^2-3x+1=0即x^2+1=3xx+1/x=(x^2+1)/x=3x/x=3答案是3
1/x+1/y=6(2x-3xy)/(x+2xy+y)=(2/y-3)/(1/y+2+1/x)题目有没有打错?再问:见补充帮忙解答再答:1/x+1/y=6(2x-3xy+2y)/(x+2xy+y)=(
(x-1/x)²=x²-2+1/x²=(x+1/x)²-4=5∴x-1/x=±√5∴x²-1/x²=(x+1/x)(x-1/x)=±3√5
8x^7/(a^8-x^8)题目里第三个分母应该是a^2+x^2吧.再问:嗯嗯,怎么算啊,麻烦你把过程写出来啊拜托啊谢谢啊再答:就是先算第一项和第二项,通分,然后在与第三项通分,以此类推。其实关键是通
1/20+2/5x-3=x/4-1/20-3x两边乘以201+8x-60=5x-1-60x63x=58x=58/63
3根号x追问:快点拜托回答:2根号x+3根号x-2根号x=3根号x
1/(x+4)-1/(x+7)=1/(x+3)-1/(x+6)(x+3)(x+6)(x+7)-(x+3)(x-6)(x+4)=(x+4)(x+7)(x+6)-(x+4)(x+7)(x+3)(x+3)(
X=六分之一Y=四分之一Z=三分之一
原式:1/20+2x/5-3=x/4-1/20-3x移项:1/20-3+1/20=-2x/5+x/4-3x-59/20=-63x得:x=59/63再问:0.7分之2M-17分之1=0.3分之M再答:2
1/x(x+3)+1/(x+3)(x+6)+1/(x+6)(x+9)=3/2(x+9)(1/3)×[3/x(x+3)+3/(x+3)(x+6)+3/(x+6)(x+9)]=3/2(x+9)(1/3)[
1题目是:x²/(x²-2)=3,求[1/(1-x)-1/(1+x)]/[x/(x²-1)+x]吧?如果是这样,那么由x²/(x²-2)=3得,x
X-1分之3减X加一分之2等于X的平方减-分之一3/(x-1)-2/(x+1)=1/(x²-1)(3x+3-2x+2)/(x²-1)=1/(x²-1)∴x+5=1x=-4
1/x-1/y=3y-x=3xy(x-2xy-y)/(2x+3xy-2y)=(-3xy-2xy)/(-6xy+3xy)=5/3
1/x-1/y=3(x-y)/xy=3x-y=3xy;(2x-2y+3xy)/(x-2xy-y)=(2(x-y)+3xy)/(x-y-2xy)=(2(3xy)+3xy)/(3xy-2xy)=9xy/x
上下同乘33xy=y-x代入替换掉3xy加减下约掉x-y得13/7
1/x(x+1)=1/x-1/(x+1)1/(x+1)(x+2)=1/(x+1)-1/(x+2)后面以此类推原式=1/x-1/(x+1)+1/(x+1)-1/(x+2)+……+1/(x+1998)-1
x+1/x=3两边乘以x:x^2-3x+1=0得到:x=(3+根5)/2或者x=(3-根5)/2又由于x大于x分之一,应取x=(3+根5)/2,则1/x=(3-根5)/2x-1/x=根5=2.236
稍等一下再答:再答:望采纳
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