X平方 10x 21=0因式分解解方程
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3x²+5x=0x(3x+5)=0∴x=0x=-5/3(2a-1)²=02a-1=0a=1/2(2x-5)²=92x-5=32x-5=-3x=4x=1(2x+x-1)(2
2x²+x-1=0(2x-1)(x+1)=02x-1=0或x+1=0x1=1/2x2=-1
(x+3)²=2x+6(x+3)²-(2x+6)=0(x+3)²-2(x+3)=0(x+3)(x+3-2)=0(x+3)(x+1)=0x+3=0或x+1=0x1=-3,x
错了改一下(2x+5)²-6(2x+5)+9=0[(2x+5)-3]²=0(2x+2)²=02x+2=0x=-1
3x的平方-6x=-33(x^2-2x+1)=03*(x-1)^2=0x=1
5x平方-2x-7=0(5x-7)(x+2)=0x1=7/5x2=-2
1/2x²+x+1/2=0x²+2x+1=0(x+1)²=0解得:x=-1
把(x-3)作为公因数提出来(x-3)*(x-3+4x)=0(x-3)*(5x-3)=0所以x1=3,x2=3/5=0.6
9(x-1)²-(x+2)²=09(x-1)²=(x+2)²3(x-1)=x+2或3(x-1)=-x-23x-3=x+2或3x-3=-x-22x=5或4x=1x
x(x-2)=0x=0,x=2再问:(y-5)(y+7)??
4x^2-25x+6=0(4x-1)(x-6)=0x1=1/4,x2=6
2(2x-3)^2-3(2x-3)=0(2(2x-3)-3)*(2x-3)=0(4x-9)*(2x-3)=0x1=3/2或9/4
等于6x²+7x+2=02132(交叉相乘)(2x+1)(3x+2)=0x=-1/2x=-2/3
(X-1)(X-6)=0所以得x=1或者x=6
a^2表示a的平方(2x+3)^2=(2x+3)(2x+3)(2x+3)-(2x+3)*1=0(2x+3)(2x+2)=0x1=-3/2,x2=-1
这么多题一点分都没有啊?x-4=(x-4)²当x-4=0时,x=4,满足方程当x-4≠0时,1=x-4,x=5所以x=4或x=5(5x-1)(2x+4)=3x+62(5x-1)(x+2)=3
5x²-4x=0x﹙5x-4﹚=0x1=0x2=4/5.
(3x+2)平方=4(x一3)平方(3x+2)²-4(x一3)²=0[(3x-2)+2(x-3)][(3x-2)-2(x-3)]=0(3x-2+2x-6)(3x-2-2x+6)=0
(x-1)(2x+3)+x(1-x)=0(x-1)(2x+3)-x(x-1)=0(x-1)(2x+3-x)=0(x-1)(x+3)=0x-1=0x=1x+3=0x=-3
3x²-6x=-4x+83x²-2x-8=0(3x+4)(x-2)=0x=-4/3,2再问:第三步能详细点吗谢谢--再答:十字相乘法:3x41x-2————-6x+4x=-2x