x根号xy除以(y根号y分子x
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题是这样的吧:[(√x-√y)^3+2x√x+y√y]/(x√x+y√y)+[3√(xy)-3y]/(x-y)原式=[(x√x-3x√y+3y√x-y√y)+2x√x+y√y]/(x√x+y√y)+[
化简约分得,2x倍根号x!
.(x-4根号xy+4y)除以(根号x-2根号y)+(2根号xy+x)乘以根号x分之一=(根号x-2根号Y)^2/(根号X-2根号Y)+(2根号XY+X)*根号X/X=根号X-2根号Y+(2X根号Y+
[(x×根号x+x×根号y)/(xy-y²)]-[(x+根号下xy+y)/(x×根号x-y×根号y)]=(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)=[x
(x√x+x√y)/(xy-y^2)-[x+√(xy)+y]/(x√x-y√y)=[x(√x+√y)/[y(√x-√y)(√x+√y)]-[x+√(xy)+y]/{(√x-√y)[x+√(xy)+y]
额,题目很长,我读出二层意思,题中有2个/,哪一个最长啊?也就是哪个是哪个的被除数.
根号32x除以根号2xy乘以2根号y的三次方=(4√2x)÷(√2xy)×(2√y³)=4÷(√y)×(2y√y)=8y
原式=1÷2×√[xy/(y²/x)]=1/2×√(x²y/y²)=x√y/(2y)
(y√x+x√y)/(xy-y²)-(x+√xy+y)/(x√x-y√y)=√xy(√x+√y)/[y(√x+√y)(√x-√y)]-(x+√xy+y)/[(√x-√y)(x+√xy+y)]
由x-√xy-2y=0可知,(√x+√y)(√x-2√y)=0解得√x=2√y,即x=4y则(2x-√xy)/(y+2√xy)=(2x-2y)/(y+4y)=6/5
2√(x²y)/3√(xy)=2√x√(xy)/3√(xy)=2(√x)/3
((x-y)/(√x+√y))-(x+y-2√xy)/(√x-√y),分母有理化,第一个式子分母乘以√x-√y,又(x+y-2√xy)=(√x-√y)(√x-√y),所以原式等于√x-√y-(√x-√
=(√x+√y)²/(√x+√y)=√x+√y
1原式=X+Y/根号X+根号Y+(2根号XY/根号X+根号Y)=根号X加Y的二次方/根号X加根号Y=根号X+根号Y2原式=(a根号a+b根号b)/(a+b-根号ab)+(根号a+2)的2次方/(根号a
可知x≥0,y≥0(x-y)/(√x+√y)-(x-2√xy+y)/(√x-√y)=(√x+√y)(√x-√y)/(√x+√y)-(√x-√y)²/(√x-√y)=(√x-√y)-(√x-√
(x-y)/(√x-√y)=(√X+√y)(√x-√y)/(√x-√y)=√x+√y
√3xy/√(y/3x)=√3xy/√(3xy/9x)=√3xy/(√3xy)/3x=3x
原式=5x根号(xy)/3根号(y/x)*1/3根号(x/y)=5/9*根号(xy*x/y*x/y)=5x/9y根号(xy)