x的y次方-y的x次方=0隐函数求导-搜答案-智慧作业帮

∵(x-2008)²≥0,(y+2007)^4≥0,(x-2008)²+(y+2007)^4=0∴x-2008=y+2007=0∴x=2008,y=-2007∴(x+y)^2012

由x^(x+y)=y^12得x+y=logx(y^12)……………①由y^(x+y)=x^3得x+y=logy(x^3)……………②所以logx(y^12)=logy(x^3)即12logx(y)=3

x的2次方+y的2次方-4x+6y+13=0(x^2-4x+4)+(y^2+6y+9)=0(x-2)^2+(y+3)^2=0因为(x-2)^2>=0(y+3)^2>=0所以(x-2)^2=0(y+3)

(x^y×y^y)/(x^x×y^y)=x^(y-x)×y^(x-y)因为x＞y＞0原式=x^-(x-y)×y^(x-y)=[y^(x-y)]/[x^(x-y)]=(y/x)^(x-y)

Y=sinx的X次方求导

详细解答请见图片,点击放大,再点击再放大.

x+9y=y-3x4x=-8yx=-2y则x²=4y²所以原式=(4y²-y²)/(4y²+y²)=3y²/5y²=3/

x^(x^x)*(x^x*(log(x)+1)*log(x)+x^x/x)x/x\(x)|xx|即x|x(log(x)+1)log(x)+----|\x/

x≥0,且x≠3

|x-1|+(y+2)²=0所以x=1y=-2x+y=-1-1的2013次方等于-1

e^(x+y)-e^x+[e^(x+y)+e^y]•dy/dx=0[e^(x+y)+e^y]•dy/dx=e^x-e^(x+y)=e^x•(1-e^y)dy/dx=

原式=(X+2)平方+(Y-3)平方=0则X=-2,Y=3X的Y次方等于-8.

X,Y分别为-2,3.原式可化简为（X+2）的平方+（Y-3）的平方=0,很明显X+2与Y-3都必须为0,得X=-2,Y=3.祝你进步.

解原式=(x^2+y^2)-(xy)^2=(x^2+xy+y^2)(x^2-xy+y^2)

[x^m]^n=x^(mn)(xy)^m=x^m*y^mx^(2y)=(x^2)^y(2x)^y=2^y*x^yx^(3y)=(x^3)^y(3x)^y=3^y*x^y

-(x+y)的10次方÷（x+y)的7次方÷（x+y)的2次方=-（x+y）^(10-7-2)=-(x+y)

y-xe^y+x=0两边求导：y'-e^y-xe^y*y'+1=0【(xe^y)'=x'(e^y)+x*(e^y)'=e^y+xe^y*y'】(1-xe^y)y'=e^y-1y'=(e^y-1)/(1

(x—y)的2次方×（x—y)的5次方×（y-x)=-(x-y)的2次方×（x-y)的5次方×（x-y)=-(x-y)的(2+5+1)次方=-(x-y)的8次方

原式=（x-3y）（x-4y）=0所以x=3y或x=4y所以y/x=1/3或y/x=1/4因式分解用十字相乘法,初二的应该会