x的平方-4分之8=2-x分之3-x-1-搜答案-智慧作业帮

2x=1详细请看图

x+2分之1+x分之1=x的平方+2x分之321/(x+2)+1/x=32/(x²+2x)去分母x+x+2=32x=15检验：左边=1/17+1/15=32/255右边=32/(225+30

(xx-8x+16)/(xx-4x+4)+[1+2/(x-2)][1+2/(x-2)]=2x/(x-2)(x-4)^2/(x-2)^2+[1+2/(x-2)]^2=2x/(x-2)[1-2/(x-2)

2/(x-2)+6x/(x²-4)=3/(x+2)乘以(x²-4)得2(x+2)+6x=3(x-2)2x+4+6x=3x-68x-3x=-6-45x=-10x=-2经检验,当x=-

变形为x（x+3)分之8-4x+x=3分之2x-3=2通分x（x+3）分之8-4x+x(2x-3)=2x(x+3)分之8+2x方-7x=22x方+6x=8+2x方-7x13x=8x=8/13

1/x+2/(x-1)=2/(x^2-x)1/x+2/(x-1)-2/(x^2-x)=0(x-1)/x(x-1)+2x/x(x-1)-2/x(x-1)=0[(x-1)+2x-2]/x(x-1)=0(3

解题思路：先解方程求出x，再化简另一分式并把x值代入计算即可解题过程：解：经检验是原方程的解。

=x/(x+4)(x-4)÷(2x+8+x²-4x)/(x+4)(x-4)=x/(x²-2x+8)

2x/3=x²/12+3/x²+4/xx²/12+3/x²=2x/3-4/xx²/4+9/x²=2x-12/x(x/2-3/x)²

=x/(x+2)(x-2)-(x-2)/(x+2)(x-2)=[x-(x-2)]/(x+2)(x-2)=2/(x²-4)

1、原式=[(4+x)(4-x)/(x+4)^2]÷[(x-4)/2(x+4)]×[(x-2)/(x+2)]=2(2-x)/(x+2)；2、原式=[(a+2)/a(a-2)-(a-1)/(a-2)^2

x/(x+2)-(x+2)/(x-2)=8/(x^2-4)x(x-2)-(x+2)^2=8x^2-2x-x^2-4x-4=8-6x=12x=-2

1分之6..

x-3分之8=2x-3=8/2=4x=7x+4分之3-x=1两边乘x-43-x=x-4x=7/2x-4分之1=x的平方-16分之4两边乘(x+4)(x-4)x+4=4x=0x-3分之2-x=1减去3-

x/(1-x)+x/(1+x)+2x/(1+x^2)+4x/(1+x^4)=[x(1+x)+x(1-x)]/(1-x^2)+2x/(1+x^2)+4x/(1+x^4)=2x/(1-x^2)+2x/(1

原式得：(x+4)(x-4)/(x-4)²+x/(x-4)=(x+4)/(x-4)+x/(x-4)=(2x²-4x+16)/(x²-16)

x+2分之x-x-2分之x+2=x的平方-4分之8x+x/2-x-x/2+2=x^2-8/42=x^2-2x^2=4x=±2

x1=1+根号3x2=1-根号3再问：有过程吗再答：x+x/2+x-x/2=x平方-8/42x=x平方-2移项x平方-2x-2=0x平方-2x+1-3=0（x-1）平方=3x-1=正负根号3x=1+根

这种表达方式,容易导致【歧义】,以后可以多加括号的1/(x+1)+2/(x-2)=-8/(x^2-4)[(x-2)+2(x+1)]/[(x+1)(x-2)]=-8/[(x-2)(x+2)]3x/(x+

原式=（x+2）²/（x+2）（x-2）-x/(x-2)=(x+2)/(x-2)-x/(x-2)=2/(x-2)