x的平方-x的三次方分之2的五次方展开式的常数项-搜答案-智慧作业帮

(2x²)³-6x³(x³+2x²+x)=8x⁶-6x⁶-12x⁵-6x⁴=2x⁶-12x

（2x的平方）的三次方-6x的三次方乘（x的三次方+2x的平方+x)=8x^6-6x^6-12x^5-6x^4=2x^6-12x^5-6x^4=2x^4(x^2-6x-3)

1.原式x^4+2x^3+3x^2+2x+1=x^4+2x^2+1+2x^3+x^2+2x=(x^2+1)^2+x^3+x+x^3+x^2+x=(x^2+1)^2+x(x^2+1)+x(x^2+x+1

x3+6x2-27x=x3-9x+6x2-18x=x(x+3)(x-3)+6x(x-3)=(x-3)(x2+3x+6x)=x(x-3)(x+9)

化简得(16a²+64a-27／64aX²)／X²将数字带入得答案为261／128

=8x的6次方-6x³(x³+2x²+x)=8x的6次方-6x的6次方-12x的5次方-6的4次方=2x的6次方-12x的5次方-6的4次方

=8x²y^4×3x/(-4y³)×(-2)/x²y=12x

3x的三次方-[x的三次方+（6x的平方-7x)]-2(x的三次方-3x的平方-4x)=3x³-x³-6x²+7x+2x³-6x²-8x=4x

先分解因式,后乘法.(X^4-Y^4)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X+Y)(X^2+Y^2)/(X^3+X^2Y+XY^2+Y^3)=(X-Y)(X^3+X^2Y+XY^2+

x(x-1)(x-2)³(x+1)(x-1)(x-1)(x²+x+1)/[(3-4x)(x²+x+2)]>0x(x-1)³(x-2)³(x+1)(x&

x²y³-2x(4xy³)=x²y³-2x²y³=-x²y³

(x²)³×x²×(2x)²=x^6×x²×4x²=4x^(6+2+2)=4x^10

是的,都不对呀.等于X(X+1),提公因式,你如果不会可以把数字带进去呀.你看比如5.5²+5=30,而,2×5²=50呀.5³=125呀.

(x的三次方分之1-x的平方分之1)·x-1分之x的三次方=(1/x³-1/x²)×x³/(x-1)=（1/x³-x/x³)×x³/(x-1

原式=[(X+2)(X-2)/(X+1)]²÷[(X-1)²/(X+1)(X-1)*[X/(X+2)}^3=X^3(X+2)²(X-2)²(X+1)(X-1)÷

∫x³/(x²+1)dx=∫(x³+x-x)/(x²+1)dx=∫xdx-∫x/(x²+1)dx=(1/2)x²-(1/2)∫1/(x

原式=x(x²-8x+12)=x(x-2)(x-6)

(3x分之y)的平方×(-y分之x)的三次方÷(-x分之2y)方=(y²/9x²)(-x³/y³)(x²/4y²)=-x³/36y