y=根号3sinx cosx的最大值单调增区间对称轴方程

f(x)=2sin平方x-根号3sinxcosx+cos平方x=1-cos2x-√3/2sin2x+1/2(cos2x+1)=1-cos2x-√3/2sin2x+1/2cos2x+1/2=3/2-1/

y=sinXcosX+（根号3）×cos平方X-根号3=1/2sin2x+√3/2(cos2x+1)-根号3=1/2sin2x+√3/2cos2x-√3/2=sin(2x+π/3)-√3/22x+π/

y=√3cos2x+sin2x=√[1²+(√3)²]sin(2x+z)=2sin(2x+z)其中tanz=√3/1=√3所以最大=2,最小=-2T=2π/2=π

函数y=sinxcosx+(√3)cos²x-(√3)/2的最小正周期y=(1/2)sin2x+(√3)(1+cos2x)/2-(√3)/2=(1/2)sin2x+(√3/2)cos2x=s

y=sinxcosx+根号3cos²x-根号3=1/2sin2x+√3/2(cos2x+1)-√3=1/2sin2x+√3/2cos2x-√3/2=sin(2x+π/3)-√3/2令2x+π

Y=√3SINXCOSX-COS²X=√3/2sin2x-(1+cos2x)/2=√3/2sin2x-1/2-cos2x/2=sin(2x-∏/6)-1/2ymax=1/2

首先化简一下函数表达式y=根号3（sinxcosx）-cosx的平方y=2cosx(sinxcos30°－cosxsin30°)y=2cosxsin(x-30°)求导有y'=2[-sinxsin(x-

y=1/2sin2x+sqr(3)/2*(1+cox(2x))-sqr(3)=sin(2x+π/3)-sqr(3)/2对称中心横坐标可令sin(2x+π/3)=02x+π/3=kπx=kπ/2-π/6

sinxcosx=1/2sin2xcos²x=1/2(1+cos2x)所以原式=1/2sin2x+√3/2(1+cos2x)-√3/2=1/2sin2x+√3/2cos2x=sin(2x+6

y=√3cos²x+sinxcosx=(√3/2)[cos2x+1]+(1/2)sin2x=sin(2x+π/3)+√3/2所以值域为[-1+√3/2,1+√3/2]最小正周期为2π/2=π

y=sinx+cosx+sinxcosx+1y'=cosx-sinx-(sinx)^2+(cosx)^2=(cosx+1/2)^2-(sinx+1/2)^2=(cosx+sinx+1)(cosx-si

y=1-4(sinx)^2-2倍根号3sin（2x）=1-2（1-cos2x）-2倍根号3sin（2x）=4sin（π/6-2x）-1当x∈[0,π/2],π/6-2x属于[-5π/6,π/6]所以最

y=sinxcosx+√3cos²x-√3/2=1/2*(2sinxcosx)+√3/2(2cos²x-1)=1/2*sin2x+√3/2cos2x.正弦余弦的二倍角公式=sin(

y=sinxcosx+根号3cos^2x＝(1/2)sin2x＋根号3×(1＋cos2x)／2＝(1/2)sin2x＋(根号3／2)cos2x＋根号3／2＝sin(2x＋60°)＋根号3／2当2x＋6

1.y=sinxcosx=1/2*sin2x,周期pai,值域《1/2,-1/2》；2.y=根号3cosx+sinx=2*(根号3/2cosx+1/2sinx)=2*sin(x+60),周期pai,值

y=sin²x+√3sinxcosx-1=[1-cos(2x)]/2+(√3/2)sin(2x)-1=(√3/2)sin(2x)-(1/2)cos(2x)-1/2=sin(2x-π/6)-1

解原式=2cosx(sinx*1/2+cosx√3/2)-√3sin²x+sinxcosx=cosxsinx+√3cos²x-√3sin²x+sinxcosx=2sinx

y=cos²x+2√3sinxcosx-sin²x=cos²x-sin²x+2√3sinxcosx=cos2x+2√3sinxcosx=cos2x+√3sin2

函数y=√3cos^2x+sinxcosx=√3/2*(1+cos2x)+1/2*sin2x=√3/2+√3/2*cos2x+1/2*sin2x=√3/2+sin(2x+π/3)周期T=π最大值√3/