Y的5次方 Y的4次方 1分解因式-搜答案-智慧作业帮

4x的平方-12x的3次方=4x²(1-3x)(2)-x的平方y+4xy-5y=-y(x²-4x+5)

=七分之一x的m-1次方y的m+1次方（21xy+1）说明：把第二项作为公因式提取即可再问：打错了，这才是题目：多项式3x的m次方y的n+2次方+七分之一x的m-1次方y的n+1次方分解因式的结果是多

x^6-y^6=(x^3+y^3)(x^3-y^3)=(x+y)(x^2-xy+y^2)(x-y)(x^2+xy+y^2)=(x+y)(x-y)[x-(根号3)yi][(x+(根号3)yi][3x-(

原式=-y(4x²-4xy+y²)=-y(2x-y)²

原式：-x^4y^4+x2y2-1/81原式等于：(-1/81+1/4)-（x^4y^4-x2y2+1/4)即：71/324-(x²y²-1/2)²=[（√71）/18-

(1/2)x⁴y²-(1/8)x²y²=(1/8)x²y²(4x²-1)=(1/8)x²y²(2x+1)(2

x^6-y^6-2x³+1=x^6-2x³+1-y^6=(x^6-2x³+1)-y^6=(x³-1)²-(y³)²=(x³

3x的4次方+x的平方y-2y的平方=(x²+y)(3x²-2y)很高兴为您解答,【the1900】团队为您答题.请点击下面的【选为满意回答】按钮,再问：有过程吗，如果是一步的话有

x^3-y^3=(x-y)(x^2+y^2+xy)

原式=(4x^2)^2-72x^2y^2+(9y^2)^2=(4x^2-9y^2)^2=(2x+3y)^2*(2x-3y)^2

公因式是mn(x-y)^n所以原式=mn(x-y)^n(n-m)两项中m最低是1次,n最低原式1次而x-y是n和n+1次,则最低是n次所以公因式是mn(x原式=mn(x-y)^n*(-m)mn(x-y

a³(x+y)²-4a³c²=a³[(x+y)²-4c²]=a³[(x+y)²-(2c)²]=a&s

=(x^2-4)^2-y^2=(x^2-4+y)(x^2-4-y)

=-x³y³(x²-y²)=-x³y³(x+y)(x-y)=(a²+1+2a)(a²+1-2a)=(a+1)²

[(x-y)x]6+[(y-x)y]6=(x-y)6x6+(y-x)6y6=(x-y)6(x6+y6)=(x-y)6[(x2)3+(y2)3]=(x-y)6(x2+y2)(x4-x2y2+y4)欢迎来

y^3-4x^2y=y(y^2-4x^2)=y(y+2x)(y-2x)

x^4-8x^2y^2+16y^4=(x^2-4y^2)^2=(x+2y)^2(x-2y)^2

(x+y)^3(x-y)-(x+y)(x-y)^3=(x+y)(x-y)[(x+y)^2-(x-y)^2]=(x+y)(x-y)(x+y+x-y)(x+y-x+y)=4xy(x+y)(x-y)

6x的n+1次方+5x的n次方y-4x的n-1次方y²=x^(n-1)(6x^2+5xy-4y^2)=x^(n-1)(2x-y)(3x+4y)

x的4次方-10x的平方y的平方+9y的4次方=(x^2-y^2)(x^2-9y^2)=(x+y)(x-y)(x+3y)(x-3y)