∫((3x^4+2x^2)/(x^2+1))dx

来源：学生作业帮编辑：作业帮分类：数学作业时间：2024/10/06 15:24:07

答：
(3x^4+2x^2)/(x^2+1)
=[3(x^2+1)x^2-(x^2+1)+1]/(x^2+1)
=3x^2-1+1/(x^2+1)
∫((3x^4+2x^2)/(x^2+1))dx
=∫(3x^2-1)dx+∫[1/(x^2+1)]dx
=x^3-x+arctanx+C

∫(3x^4+x^2)/(x^2+1)dx ∫2^x*3^x/(9^x-4^x) dx ∫（x^2+1/x^4)dx ∫1/(x^4-x^2)dx ∫(1-x)^2/x^3 dx ∫(x-1)^2/x^3 dx ∫x^3/1+x^2 dx ∫(X^3)/(1+X^2)dx ∫ [(x^3-2x^2+x+1)/(x^4+5x^2+4)]dx 计算 ∫（x^4-2x^3+x^2+1）/x（x-1)² dx x-9/[(根号)x]+3 dx ∫ x+1/[(根号)x] dx ∫ [（3-x^2）]^2 dx ∫（(x+2)/4x(x^2-1)）dx