若数列bn满足bn=n^2/2^(n+1),证明bn
18、一道数列题已求出数列An=2n.若数列Bn满足B(n+1)=Bn^2-(n-2)Bn+3,Bn大于等于1,证明:B
若数列bn满足b1=2,且bn+1=bn+2^n+n,求数列bn的通项公式.
an=2*3^n-1 若数列bn满足bn=an+(-1)^n*ln(an),求数列bn前n项和Sn
已知数列bn满足bn=b^2n,其前n项和为Tn,求(1-bn)/Tn
数列an的前n项和为Sn=2^n-1,设bn满足bn=an+1/an,判断并证明bn 的单调性
已知数列{an}和{bn}满足关系式:bn=a1+a2+a3+...+an/n(n属于N*) (1)若bn=n^2,求数
已知数列bn,满足b1=1,b2=5,bn+1=5bn-6bn-1(n≥2),若数列an满足a1=1,an=bn(1/b
已知无穷数{bn}满足b1=1,bn+1-bn=(1/2)^n (n>=1),数列{bn}的通项公式是?
数列an的前n项和为Sn,Sn=4an-3,①证明an是等比数列②数列bn满足b1=2,bn+1=an+bn.求数列bn
(2)若数列{bn}满足bn=an log2 an+1,求数列{bn}的前n项和Tn
数列[an]的前n项和Sn等于2*n-1,数列[bn]满足:b1=3,bn+1=an+bn,n属于N*.1.证明数列[a
已知数列{an}{bn}满足a1=1,a2=3,b(n+1)/bn=2,bn=a(n+1)-an,(n∈正整数),求数列